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Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) – NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine th mass (in grams) of each product. g NANH2 g H2 Submit

Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) – NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine th mass (in grams) of each product. g NANH2 g H2 Submit

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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[References] CHEMWORK Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) - NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine the mass (in grams) of each product. g NaNH2 g H2 Submit Submit Answer Try Another Version 3 item attempts remaining Previous Next
Transcribed Image Text:[References] CHEMWORK Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) - NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine the mass (in grams) of each product. g NaNH2 g H2 Submit Submit Answer Try Another Version 3 item attempts remaining Previous Next
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