Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) – NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine th mass (in grams) of each product. g NANH2 g H2 Submit
Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is given below: NH3(g) + Na(s) – NANH2(s) + H2(g) Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine th mass (in grams) of each product. g NANH2 g H2 Submit
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 3ALQ: Nitrogen (N2) and hydrogen (H2)react to form ammonia (NH3). Consider the mixture of N2 and H2 in a...
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CHEMWORK
Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is
given below:
NH3(g) + Na(s) - NANH2(s) + H2(g)
Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine the
mass (in grams) of each product.
g NaNH2
g H2
Submit
Submit Answer
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Transcribed Image Text:[References]
CHEMWORK
Ammonia gas reacts with sodium metal to form sodium amide (NaNH,) and hydrogen gas. The unbalanced chemical equation for this reaction is
given below:
NH3(g) + Na(s) - NANH2(s) + H2(g)
Assuming that you start with 30.6 g of ammonia gas and 13.0 g of sodium metal and assuming that the reaction goes to completion, determine the
mass (in grams) of each product.
g NaNH2
g H2
Submit
Submit Answer
Try Another Version
3 item attempts remaining
Previous
Next
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