The component of the weight parallel to Momo's acceleration is wx = mg_______Φ. The magnitude of the frictional force is f = μk__________. The normal force on Momo is n = mg___________Φ. With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration: a =___________(__________ - μk __________
FILL IN THE BLANKS WITH THE CORRECT VALUE
Momo with mass m is sliding down an inclined plane that makes an angle Φ relative to the horizontal. The coefficient of kinetic friction between Momo and the inclined plane is μk. Obtain an expression for Momo's acceleration along the incline.
Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis.
The component of the weight parallel to Momo's acceleration is wx = mg_______Φ.
The magnitude of the frictional force is f = μk__________.
The normal force on Momo is n = mg___________Φ.
With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration:
a =___________(__________ - μk __________)
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images