F2=1.96 NT90 F= 0.98 N, 145on F =1.47 N, 30 180° E= 3.30 N, 262°
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In an experiment about vector addition, a group of students has obtain the forces shown in the force table below. Calculate analytically the magnitude of the resultant of forces F1, F2, and F3 on the force table.
![F2 = 1.96 NT 90°
Fs = 0.98 N, 1450
F1 =1.47 N, 30°
180°
0°
E = 3.30 N, 262°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd355daf7-16a7-4040-80be-b01fe9d2d357%2Fe6ac07fa-082e-4117-90fa-b829c6c7778e%2Fogdvpay_processed.png&w=3840&q=75)
![О 3.28 N
О 3.29 N
О 3.30 N
О 3.31 N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd355daf7-16a7-4040-80be-b01fe9d2d357%2Fe6ac07fa-082e-4117-90fa-b829c6c7778e%2F4gnh9x_processed.png&w=3840&q=75)
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