F2=1.96 NT90 F= 0.98 N, 145on F =1.47 N, 30 180° E= 3.30 N, 262°

icon
Related questions
Question

In an experiment about vector addition, a group of students has obtain the forces shown in the force table below. Calculate analytically the magnitude of the resultant of forces F1, F2, and F3 on the force table.

F2 = 1.96 NT 90°
Fs = 0.98 N, 1450
F1 =1.47 N, 30°
180°
0°
E = 3.30 N, 262°
Transcribed Image Text:F2 = 1.96 NT 90° Fs = 0.98 N, 1450 F1 =1.47 N, 30° 180° 0° E = 3.30 N, 262°
О 3.28 N
О 3.29 N
О 3.30 N
О 3.31 N
Transcribed Image Text:О 3.28 N О 3.29 N О 3.30 N О 3.31 N
Expert Solution
steps

Step by step

Solved in 3 steps with 4 images

Blurred answer