The complete elliptic integral of the first kind is the integral -п/2 de K = V1 – k² sin² 0 where 0 < k < 1 is constant. a. Show that the first four terms of the binomial series for 1/V1 – x are 1:3 x² + 1:3.5 (1 – x)-1/2 = 1 + 2.4* 2.4.6 b. From part (a) and the reduction integral Formula 67 at the back of the book, show that 1•3\2 k4 + 1•3•5 K 2 k2 + 2.4 2.4.6

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
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The complete elliptic integral of the first kind is the integral
-п/2
de
K =
V1 – k² sin² 0
where 0 < k < 1 is constant.
a. Show that the first four terms of the binomial series for
1/V1 – x are
1:3
x² +
1:3.5
(1 – x)-1/2 = 1 +
2.4*
2.4.6
b. From part (a) and the reduction integral Formula 67 at the
back of the book, show that
1•3\2
k4 +
1•3•5
K
2
k2 +
2.4
2.4.6
Transcribed Image Text:The complete elliptic integral of the first kind is the integral -п/2 de K = V1 – k² sin² 0 where 0 < k < 1 is constant. a. Show that the first four terms of the binomial series for 1/V1 – x are 1:3 x² + 1:3.5 (1 – x)-1/2 = 1 + 2.4* 2.4.6 b. From part (a) and the reduction integral Formula 67 at the back of the book, show that 1•3\2 k4 + 1•3•5 K 2 k2 + 2.4 2.4.6
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