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) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. [₁0⁰ 3 dx x² + 1 Does the series ∞ n=1 3 n² + 1 converge or diverge? ? >

) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. [₁0⁰ 3 dx x² + 1 Does the series ∞ n=1 3 n² + 1 converge or diverge? ? >

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. ∞ 1.₁ 3 dx x² + 1 = Does the series ∞ n=1 3 n² +1 converge or diverge? ?
Transcribed Image Text:) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. ∞ 1.₁ 3 dx x² + 1 = Does the series ∞ n=1 3 n² +1 converge or diverge? ?
i ) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -0. Otherwise, enter diverges. [ 8x²e-³ dx = ∞ Does the series 8n² e-n²³ converge or diverge? ? n=1 >
Transcribed Image Text:i ) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -0. Otherwise, enter diverges. [ 8x²e-³ dx = ∞ Does the series 8n² e-n²³ converge or diverge? ? n=1 >
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) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. ∞ 1.₁ 3 dx x² + 1 = Does the series ∞ n=1 3 n² +1 converge or diverge? ?
Transcribed Image Text:) Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to ∞, and -infinity if it diverges to -∞. Otherwise, enter diverges. ∞ 1.₁ 3 dx x² + 1 = Does the series ∞ n=1 3 n² +1 converge or diverge? ?
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