The collar shown slides frictionlessly along the rod and is released from rest when q 60. Each wheel has a radius of 0.8 ft and a radius of gyration of 0.5 ft, and they roll without slipping. The collar just touches the spring when the two rods are horizontal. Find a. the velocity of the collar is it just reaches the spring, and b. the maximum depression of the spring. m =1 slug 1 ft m = 0.5 slug 1 ft m = 2 slugs m = 0.5 slug m = 2 slugs k= 100 lb/in

The collar shown slides frictionlessly along the rod and is released from rest when q 60. Each wheel has a radius of 0.8 ft and a radius of gyration of 0.5 ft, and they roll without slipping. The collar just touches the spring when the two rods are horizontal. Find a. the velocity of the collar is it just reaches the spring, and b. the maximum depression of the spring. m =1 slug 1 ft m = 0.5 slug 1 ft m = 2 slugs m = 0.5 slug m = 2 slugs k= 100 lb/in

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.11P: Solve Prob. 7.10 assuming that the pick-up truck has front-wheel drive.

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Concept explainers

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.

Question

L20
The collar shown slides frictionlessly along the rod and is
released from rest when q 60'. Each wheel has a radius of 0.8
ft and a radius of gyration of 0.5 ft, and they roll without
slipping. The collar just touches the spring when the two rods
are horizontal. Find
a. the velocity of the collar is it just reaches the spring, and
b. the maximum depression of the spring.
m = 1 slug
1 ft
m = 0.5 slug
1 ft
m = 2 slugs
m = 0.5 slug
m = 2 slugs
k = 100 lb/in

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