The code below is an example of what kind of loop? int x= 0; while(x<10) { x--; }
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The code below is an example of what kind of loop?
int x= 0;
while(x<10)
{
x--;
}
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- SYNTAX ERROR HELP - PYTHON This also happens for several other 'return result' lines in the code. import randomdef rollDice(): num1 = random.randint(1, 6) num2 = random.randint(1, 6) return num1, num2def determine_win_or_lose(num1, num2): result = -1 total = num1 + num2print(f"You rolled {num1} + {num2} = {total}")if total == 2 or total == 3 or total == 12: result = 0elif total == 7 or total == 11: result = 1else: print(f"point is {total}") x = determinePointValueResult(total)if x == 1: result = 1else: result = 0 return resultdef determinePointValueResult(pointValue): total = 0 result = -1while total != 7 and total != pointValue: num1, num2 = rollDice() total = num1 + num2if total == pointValue: result = 1elif total == 7: result = 0print(f"You rolled {num1} + {num2} = {total}")return resultwhile i < n: num1, num2 = rollDice() result = determine_win_or_lose(num1, num2)if result == 1: winCounter += 1 print("You…void traceMe(double x, double y) { double z; z = (pow(x, y)); cout « fixed « showpoint <« setprecision(2)<« x « ", " « y « ", " « z « endl; int main() double one=2, two=6; traceMe(two, one); 2.00 , 6,00 , 36.00 6.00 , 2.00 , 36.00 6.00 , 2,00 , 64.00 O 6.00, 2.00, 4,00int main(){ string str; int count = 0; // user input cout << "Enter string: "; cin >> str; int n = str.length(); // iterating over the string for (int i = 0; i < n - 1; i++) { // calling the fucntion to find the palidrome strings from the user input if (isPalindrome(0, i, str) && isPalindrome(i + 1, n - 1, str)) { // if 2 substring are palindrome then print them and increment count for (int x = 0; x < i + 1; x++) cout << str[x]; cout << " "; for (int x = i + 1; x < n; x++) cout << str[x]; count++; // break the loop after printing the palindrom string break; } } // if count is 0 then no palindrome subtring pair found if (count == 0) cout << "NO";} change this code to stdio.h string.h
- No plagiarism pleaseSimple try-catch Program This lab is a simple program that demonstrates how try-catch works. You will notice the output when you enter incorrect input (for example, enter a string or double instead of an integer). Type up the code, execute and submit the results ONLY. Do at least 2 valid inputs and 1 invalid. NOTE: The program stops executing after it encounters an error! CODE: import java.util.Scanner; public class TryCatchExampleSimple { public static void main(String[] args) { Scanner input = new Scanner(System.in); int num = 0; System.out.println("Even number tester.\n"); System.out.println("Enter your name: "); String name input.nextLine(); } } while (true) { try { System.out.println("Enter an integer : "); num= input.nextInt (); } int mod = num%2; if (mod == 0) " System.out.println(name + else " System.out.println(name + num = 0; } catch (Exception e) { break; > System.out.println("ERROR: The number you entered is illegal!"); System.out.println("Exception error: "+e.toString());…int j; switch (i) { case 0: j = 2*i; break; case 1: j = -i; break; default: j = -2*i; } What is j if i = 1? What is j if i = -1?
- //Assignment 06 */public static void main[](String[] args) { String pass= "ICS 111"; System.out.printIn(valPassword(pass));} /* public static boolean valPassword(String password){ if(password.length() > 6) { if(checkPass(password) { return true; } else { return false; } }else System.out.print("Too small"); return false;} public static boolean checkPass (String password){ boolean hasNum=false; boolean hasCap = false; boolean hasLow = false; char c; for(int i = 0; i < password.length(); i++) { c = password.charAt(1); if(Character.isDigit(c)); { hasNum = true; } else if(Character.isUpperCase(c)) { hasCap = true; } else if(Character.isLowerCase(c)) { hasLow = true; } } return true; { return false; } }Downvote gurantee for wrong reason 1._- DO NOT COPY FROM OTHER WEBSITES Correct answer will be Upvoted else downvoted. Thank you!!!.in c++ how can i print out a filled in circle with "*" like in the image
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