The circuit was in steady state for a long time before the switch was closed. Please calculate Vc₂ at the given times, where L = 28 mH, C₁ = 2 nF. 10 V t = 0 VC1 C₁ IL Vez 16 nF inn V₁₂ |t=0|t=0+ t = 1s | Unit Maximum current that will be passing through the inductor after the switch is moved V ILmax ☐ mA
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.The figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μWplease solve quickly.
- Using the series circuit in Figure 3 consisting of a voltage source V, the resistor R and the fully uncharged capacitor C, how to find the value of the capacitance C considering as known data the time constant of the circuit T and the value of the resistor R? V ww RThe following figure represents an RC-Circuit with the switch. In Figure A, the capacitor is initially uncharged. In Figure B, the capacitor is initially fully charged. 1) Draw and label the current direction immediately after the switch is closed for each figure. 2) Consider Figure A. What is the voltage across the capacitor as t → 0? Explain. 3) Consider Figure B. Is the voltage across the resistor increasing, decreasing or staying the same as t → 0? Explain. A) B) R CConsider the circuit shown below, with an initially uncharged capacitor C and two identical resistors R. R O www V I C I₂ R C R At the instant the switch is closed, the current through the capacitor will be: zero At the instant the switch is closed, the current through the right-side resistor will be: V/R, directed Up After the switch has been closed for a very long time, it is opened. The current through the right-side resistor will be V/R, directed Down The switch is closed at t = 0. At t = ~ (long after) the current through the right-side resistor will be: V/2R, directed Down ✓ The switch is closed at t = 0. At t = ~ (long after) the current through the capacitor will be: V/2R, directed Up After the switch has been closed for a very long time, it is ope ed. The current through the be? V/R, directed Down pacitor will
- For the circuit below, determine the current in each branch and the potential difference in the inductor immediately after switch S isclosed. After a long time the switch S is then opened. What are the currents in each branch and the potential difference in the inductor at that moment?Please answer in typing format please ASAP for Please answer in typing format please ASAP for Please I will like itSwitch S in in the figure is closed at time t = 0, to begin charging an initially uncharged capacitor of capacitance C= 17.9 µF through a resistor of resistance R = 22.7 Q. At what time is the potential across the capacitor equal to that across the resistor? Number i Units S R C
- The voltage across a 200-mH inductor is given by v = 3t2 + 2t + 4V. Determine the current through the inductor after 1s. Assume that i(0) = 0What is the maximum energy Emax stored in the capacitor at any time during the current oscillations? Express your answer in joules. How many times per second does the capacitor contain the amount of energy found in part A? Express your answer in times per second.You are an electrician working in an industrial plant. You discover the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-V AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 μF and a voltage rating of 240 V AC. The only 10-μF capacitor in the storeroom is marked with a voltage rating 350 VDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.