The circuit below was connected to investigate the relation between the voltage and current in the diode. For each setting of the voltage source, E, the current through and the voltage across the diode were recorded and tabulated in the table below. a) Find the DC resistance of the diode when the voltage across it is 0.57 V. Repeat the calculation when the voltage across the diode is 0.66 V. Compare the two answers. b) Find the average resistance of the diode when an AC generator causes the voltage across the diode to vary between 0.57 and 0.63 V. c) Derive an expression for the AC (dynamic) resistance of the diode, using Shockley's equation, and use it to find the diode's AC resistance at room temperature when V, is equal to 0.62 V. Hint: Write down the Shockley's equation and take the derivative, which corresponds to the slope (inverse of AC resistance) of the tangent at a point. R + E Vp Vp (V) Ip (mA) 0.57 0.62 0.63 0.66 51.1 0.55 0.56 0.61 0.67 0.68 0.705 1.04 1.54 7.33 10.8 15.9 75.3 110.8

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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The circuit below was connected to investigate the relation between the voltage and
current in the diode. For each setting of the voltage source, E, the current through and
the voltage across the diode were recorded and tabulated in the table below.
a) Find the DC resistance of the diode when the voltage across it is 0.57 V.
Repeat the calculation when the voltage across the diode is 0.66 V. Compare
the two answers.
b) Find the average resistance of the diode when an AC generator causes the
voltage across the diode to vary between 0.57 and 0.63 V.
c) Derive an expression for the AC (dynamic) resistance of the diode, using
Shockley's equation, and use it to find the diode's AC resistance at room
temperature when V, is equal to 0.62 V. Hint: Write down the Shockley's
equation and take the derivative, which corresponds to the slope (inverse of
AC resistance) of the tangent at a point.
R
+
I,
E
Vp
Vp (V)
Ip (mA) 0.705 1.04
0.56
0.61
0.62
0.63
0.66
51.1
0.67
75.3
0.55
0.57
0.68
1.54
7.33
10.8
15.9
110.8
Transcribed Image Text:The circuit below was connected to investigate the relation between the voltage and current in the diode. For each setting of the voltage source, E, the current through and the voltage across the diode were recorded and tabulated in the table below. a) Find the DC resistance of the diode when the voltage across it is 0.57 V. Repeat the calculation when the voltage across the diode is 0.66 V. Compare the two answers. b) Find the average resistance of the diode when an AC generator causes the voltage across the diode to vary between 0.57 and 0.63 V. c) Derive an expression for the AC (dynamic) resistance of the diode, using Shockley's equation, and use it to find the diode's AC resistance at room temperature when V, is equal to 0.62 V. Hint: Write down the Shockley's equation and take the derivative, which corresponds to the slope (inverse of AC resistance) of the tangent at a point. R + I, E Vp Vp (V) Ip (mA) 0.705 1.04 0.56 0.61 0.62 0.63 0.66 51.1 0.67 75.3 0.55 0.57 0.68 1.54 7.33 10.8 15.9 110.8
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