The chemical reaction shown was performed and the concentration of CCl4CCl4 was measured over time.   Cl2(g)+CHCl3(g)⟶HCl(g)+CCl4(g)Cl2(g)+CHCl3(g)⟶HCl(g)+CCl4(g)   The [CCl4]after 9 s was 0.049 mol/L. After 138 s, the [CCl4] was 0.451 mol/L. Calculate the rate of reaction.

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