The cation M2+ reacts with NH3 to form a series of complex ions as follows: + NH3 = M(NH3)²+ M(NH3)2+ + NH3 = M(NH3),2+ M(NH3)22+ + NH3= M(NH3);2+ M²+ K1 = 102 K2 = 103 K3 = 102 A 1.0 × 10³ mol sample of M(NO3)2 is added to 1.0 L of 15.0 M NH3 (K, = 1.8 ×x 10-5). Choose the dominant species in this solution. %3D M2+ M(NH3)²+ M(NH3),2+ M(NH3);2+ M(NO3)2

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I know the answer is D and that the K1 X K2 X K3 = K. And these cancel out to give D as the product, but won't that be the case for any series of reactions? I wouldn't think that automatically makes D the dominant species but maybe it does. Could you explain how the dominant special could be anything other than the final product in a reaction series based of K values?

The cation M2+ reacts with NH3 to form a series of complex ions as follows:
M2+ + NH3 = M(NH3)²+
K1 = 102
M(NH3)2+ + NH3 M(NH3),
M(NH3)22+ + NH3 → M(NH3);?
2+
K2 = 103
%3D
K3 = 10²
A 1.0 x 10-3 mol sample of M(N03)2 is added to 1.0 L of 15.0 M NH3 (Kp = 1.8 × 10). Choose the
dominant species in this solution.
M²+
M(NH3)²+
Ο ΜΝΗ3)>.
2+
M(NH3);?
2+
O M(NO3)2
Transcribed Image Text:The cation M2+ reacts with NH3 to form a series of complex ions as follows: M2+ + NH3 = M(NH3)²+ K1 = 102 M(NH3)2+ + NH3 M(NH3), M(NH3)22+ + NH3 → M(NH3);? 2+ K2 = 103 %3D K3 = 10² A 1.0 x 10-3 mol sample of M(N03)2 is added to 1.0 L of 15.0 M NH3 (Kp = 1.8 × 10). Choose the dominant species in this solution. M²+ M(NH3)²+ Ο ΜΝΗ3)>. 2+ M(NH3);? 2+ O M(NO3)2
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