Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches. Use the References to access important values if needed for this question. The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCI5(g) =PCI3(g) + Cl2(g) Assuming that you start with only PCI5, describe the relative abundance of each species present at equilibrium. Clear All [PCI5] Higher [Cl2] Lower [PCI3] Can't tell

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Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty
for missing matches.
Use the References to access important values if needed for this question.
The equilibrium constant, Ke, for the following reaction is 1.20×10 2 at 500 K.
PCI5(g) =PCI3(g) + Cl2(g)
Assuming that you start with only PCI5, describe the relative abundance of each species present at equilibrium.
Clear All
[PCI5]
Higher
[Cl2]
Lower
[PCI3]
Can't tell
Transcribed Image Text:Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches. Use the References to access important values if needed for this question. The equilibrium constant, Ke, for the following reaction is 1.20×10 2 at 500 K. PCI5(g) =PCI3(g) + Cl2(g) Assuming that you start with only PCI5, describe the relative abundance of each species present at equilibrium. Clear All [PCI5] Higher [Cl2] Lower [PCI3] Can't tell
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