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The capacitor in the figure below is uncharged for t < 0. If E = 8.02 V, R = 58.9 2, and C = 4.00 µF, use Kirchhoff's loop rule to find the current (in A) through the resistor at the following times. R HINT (a) t = 0, when the switch is closed (b) t = t, one time constant after the switch is closed A

The capacitor in the figure below is uncharged for t < 0. If E = 8.02 V, R = 58.9 2, and C = 4.00 µF, use Kirchhoff's loop rule to find the current (in A) through the resistor at the following times. R HINT (a) t = 0, when the switch is closed (b) t = t, one time constant after the switch is closed A

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The capacitor in the figure below is uncharged for 
t < 0.
 If  = 8.02 V, R = 58.9 Ω, and C = 4.00 µF, use Kirchhoff's loop rule to find the current (in A) through the resistor at the following times.
The circuit is a rectangular loop. The bottom side of the loop has a battery labeled emf ℰ, oriented with the positive terminal to the right of the negative terminal. The right side has a resistor R. The top side contains an open switch S. The left side has a capacitor C.
HINT
(a)
t = 0,
 when the switch is closed
 A
(b)
t = ?,
 one time constant after the switch is closed
 A
The capacitor in the figure below is uncharged for \( t < 0 \). If \( \mathcal{E} = 8.02 \, \text{V} \), \( R = 58.9 \, \Omega \), and \( C = 4.00 \, \mu \text{F} \), use Kirchhoff's loop rule to find the current (in A) through the resistor at the following times. ![Circuit diagram](image_of_circuit_diagram.png) The diagram illustrates a simple RC circuit consisting of a capacitor (C), a resistor (R), and a battery with voltage \( \mathcal{E} \). A switch (S) connects the components in series. - **Component values:** - Voltage, \( \mathcal{E} = 8.02 \, \text{V} \) - Resistance, \( R = 58.9 \, \Omega \) - Capacitance, \( C = 4.00 \, \mu \text{F} \) #### Solve for: (a) \( t = 0 \), when the switch is closed: \[ \text{Current: } \_\_\_\_ \text{ A} \] (b) \( t = \tau \), one time constant after the switch is closed: \[ \text{Current: } \_\_\_\_ \text{ A} \] **HINT:** Use Kirchhoff's loop rule to solve for the current at the specified times.
Transcribed Image Text:The capacitor in the figure below is uncharged for \( t < 0 \). If \( \mathcal{E} = 8.02 \, \text{V} \), \( R = 58.9 \, \Omega \), and \( C = 4.00 \, \mu \text{F} \), use Kirchhoff's loop rule to find the current (in A) through the resistor at the following times. ![Circuit diagram](image_of_circuit_diagram.png) The diagram illustrates a simple RC circuit consisting of a capacitor (C), a resistor (R), and a battery with voltage \( \mathcal{E} \). A switch (S) connects the components in series. - **Component values:** - Voltage, \( \mathcal{E} = 8.02 \, \text{V} \) - Resistance, \( R = 58.9 \, \Omega \) - Capacitance, \( C = 4.00 \, \mu \text{F} \) #### Solve for: (a) \( t = 0 \), when the switch is closed: \[ \text{Current: } \_\_\_\_ \text{ A} \] (b) \( t = \tau \), one time constant after the switch is closed: \[ \text{Current: } \_\_\_\_ \text{ A} \] **HINT:** Use Kirchhoff's loop rule to solve for the current at the specified times.
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