S2 6 7 and 8 Situation 2:The butt connection shows 8 – 22 mm diameterA325 bolts spaced as shown. The diameter of thehole is 3 mm larger than the bolts. The thickness ofthe middle plate is 16 mm while the other platesare 12 mm. Use Si = 40 mm, S2 = 80 mm, S3 = 50mm and S4 = 100 mm.S,S2S,Allowable stresses are as follows:Steel yield strength, Fy = 248 MPaSteel ultimate strength, Fu = 400 MPaBolt shear stress, Ex = 120 MPaBearing Stress on projected area, ER = 600 MPaTensile stress on gross area = 148 MPaTensile stress on net area = 200 MPaShear stress on plates = 120 MPa6.Determine the value of T based on bolt shear.a.364.93 kNс.378.88 kNb.844.80 kNd.352.00 kNFind the value of I based on bearing of plates.7.а.364.93 kNс.378.88 kNb.844.80 KNd.352.00 kN8.Compute the value of T based on tension on the gross area.а.364.93 kNc.378.88 kNb.844.80 kNd.352.00 kN9.Solve the value of T based on tension on the net area.а.364.93 kNс.378.88 kNb.844.80 kNd.352.00 kN

Given, t1=12 mmt2=12 mm Yield strength Fy=248 MPa Fu=400 MPa FV=120 MPaFP=600 MPa s1=40 mms2=80…

The butt connection shows 8 - 22 mm diameter A325 bolts spaced as shown. The diameter of the hole is 3 mm larger than the bolts. The thickness of the middle plate is 16 mm while the other plates are 12 mm. Use Si = 40 mm, S2 = 80 mm, Sa = 50 mm and Sa = 100 mm. Situation 2:

The butt connection shows 8 - 22 mm diameter A325 bolts spaced as shown. The diameter of the hole is 3 mm larger than the bolts. The thickness of the middle plate is 16 mm while the other plates are 12 mm. Use Si = 40 mm, S2 = 80 mm, Sa = 50 mm and Sa = 100 mm. Situation 2:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

S2 6 7 and 8

Situation 2:
The butt connection shows 8 – 22 mm diameter
A325 bolts spaced as shown. The diameter of the
hole is 3 mm larger than the bolts. The thickness of
the middle plate is 16 mm while the other plates
are 12 mm. Use Si = 40 mm, S2 = 80 mm, S3 = 50
mm and S4 = 100 mm.
S,
S2
S,
Allowable stresses are as follows:
Steel yield strength, Fy = 248 MPa
Steel ultimate strength, Fu = 400 MPa
Bolt shear stress, Ex = 120 MPa
Bearing Stress on projected area, ER = 600 MPa
Tensile stress on gross area = 148 MPa
Tensile stress on net area = 200 MPa
Shear stress on plates = 120 MPa
6.
Determine the value of T based on bolt shear.
a.
364.93 kN
с.
378.88 kN
b.
844.80 kN
d.
352.00 kN
Find the value of I based on bearing of plates.
7.
а.
364.93 kN
с.
378.88 kN
b.
844.80 KN
d.
352.00 kN
8.
Compute the value of T based on tension on the gross area.
а.
364.93 kN
c.
378.88 kN
b.
844.80 kN
d.
352.00 kN
9.
Solve the value of T based on tension on the net area.
а.
364.93 kN
с.
378.88 kN
b.
844.80 kN
d.
352.00 kN

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