The boom on a 6300kg truck is used to unload a pallet of shingles of weight 7750kg . Determine the reaction at each of the two (a) rear wheels B, (b) front whe

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question

Modified exercise from the book vector mechanics for engineers: statics and dynamics th edition.Chapter 4 exercise 1

The boom on a 6300kg truck is used to unload a pallet of shingles of weight 7750kg . Determine the reaction at each of the two (a) rear wheels B, (b) front wheels C

Modified exercise from the book vector mechanics for engineers: statics and dynamics 7th edition.Chapter 4 exercise 1
The boom on a 6300kg truck is used to unload a pallet of shingles of weight 7750kg . Determine the reaction at each of the two (a) rear wheels B, (b) front wheels C
4,3 m
0,5 i
0,4 m
modified question answer based on book solution: a)51917,69N b)16752, 27
Transcribed Image Text:Modified exercise from the book vector mechanics for engineers: statics and dynamics 7th edition.Chapter 4 exercise 1 The boom on a 6300kg truck is used to unload a pallet of shingles of weight 7750kg . Determine the reaction at each of the two (a) rear wheels B, (b) front wheels C 4,3 m 0,5 i 0,4 m modified question answer based on book solution: a)51917,69N b)16752, 27
Solution of the question in chapter 4 exercise 1 of the book
EMe = 0
-(Bx5.2)N-m+(42183×0.5)N-m+15696 x(6cos15°+0.9)N-m=0(counter clockwise
Or B= 24266.34N
6m
It is the total reaction on the two rear wheels B so the reaction on each rear wheel
W= 4300kg
12133.17N
= 42183N
15
w, = 1600kg
Comment
= 15696N
To find the reactions B and c
Step 4 of 4 A
Equilibrium conditions
Substituting the value of B in equation (1)
EF, =0:
C
C = (57879 - 24266.34) N
B
C = 33612.66N
B+C-W-W, =0
So, the reaction on each front wheel 33612.66N
4.3m
0.5m
Or B+C = 42183+15696
0.4m
= 57879N ---(1)
16806.33N
Transcribed Image Text:Solution of the question in chapter 4 exercise 1 of the book EMe = 0 -(Bx5.2)N-m+(42183×0.5)N-m+15696 x(6cos15°+0.9)N-m=0(counter clockwise Or B= 24266.34N 6m It is the total reaction on the two rear wheels B so the reaction on each rear wheel W= 4300kg 12133.17N = 42183N 15 w, = 1600kg Comment = 15696N To find the reactions B and c Step 4 of 4 A Equilibrium conditions Substituting the value of B in equation (1) EF, =0: C C = (57879 - 24266.34) N B C = 33612.66N B+C-W-W, =0 So, the reaction on each front wheel 33612.66N 4.3m 0.5m Or B+C = 42183+15696 0.4m = 57879N ---(1) 16806.33N
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY