1. The displacement formulation for a plane truss is similar to that of a mass-spring system. The differences are: (1) the stiffnesses of the members are k;= (E A/L)i, where E is the modulus of elasticity, A represents the cross-sectional area and L is the length of the member; (2) there are two components of displacement at each joint. For the statically indeterminate truss shown the displacement formulation yields the symmetric equations Ku = p. where k;= (E A/L)i, where E is the modulus of elasticity. A represents the cross-sectional area and L is the length of the member; (2) there are two components of displacement at each joint. For the statically indeterminate truss shown the displacement formulation yields the symmetric equations Ku=p. where: 27.58 7.004 7.004 -7.004 0.0000 0.00001 0.0000 -24.32 29.57 -5.253 K= -7.004 -5.253 29.57 0.0000 0.0000 MN/m 0.0000 0.0000 0.0000 27.58 -7.004 0.0000 -24.32 0.0000 -7.004 29.57 Determine the displacements u; of the joints. p= >= [0000 000-45]¹KN kN 1.8m 2.4 m 14₂ U₂ ₁ +45 KN

1. The displacement formulation for a plane truss is similar to that of a mass-spring system. The differences are: (1) the stiffnesses of the members are k;= (E A/L)i, where E is the modulus of elasticity, A represents the cross-sectional area and L is the length of the member; (2) there are two components of displacement at each joint. For the statically indeterminate truss shown the displacement formulation yields the symmetric equations Ku = p. where k;= (E A/L)i, where E is the modulus of elasticity. A represents the cross-sectional area and L is the length of the member; (2) there are two components of displacement at each joint. For the statically indeterminate truss shown the displacement formulation yields the symmetric equations Ku=p. where: 27.58 7.004 7.004 -7.004 0.0000 0.00001 0.0000 -24.32 29.57 -5.253 K= -7.004 -5.253 29.57 0.0000 0.0000 MN/m 0.0000 0.0000 0.0000 27.58 -7.004 0.0000 -24.32 0.0000 -7.004 29.57 Determine the displacements u; of the joints. p= >= [0000 000-45]¹KN kN 1.8m 2.4 m 14₂ U₂ ₁ +45 KN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

Question

1. The displacement formulation for a plane truss is similar to that of a mass-spring system. The differences are: (1) the
stiffnesses of the members are k;= (E A/L);, where E is the modulus of elasticity, A represents the cross-sectional area and L
is the length of the member; (2) there are two components of displacement at each joint. For the statically indeterminate
truss shown the displacement formulation yields the symmetric equations Ku = p.
where k;= (E A/L), where E is the modulus of elasticity, A represents the cross-sectional area and L is the length of the
member; (2) there are two components of displacement at each joint. For the statically indeterminate truss shown the
displacement formulation yields the symmetric equations Ku=p. where:
27.58 7.004 -7.004 0.0000 0.00007
7.004 29.57 -5.253 0.0000 -24.32
K= -7.004 -5.253 29.57 0.0000 0.0000 MN/m
0.0000 0.0000 0.0000
27.58 -7.004
0.0000 -24.32 0.0000 -7.004 29.57
Determine the displacements u; of the joints.
P=
000-45] KN
1.8m
24m
14₂
U₁
U₂
+4₂
+45 KN

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