The boiling point of pure ethanol (C₂H₂OH, MM = 46.07 g/mol) is 78.4 °C. A solution is made using 100.0 g of ethanol (the solvent) and 24.1 g of glucose (MM = 180.16 g/mol). What is the boiling point of this solution, in °C? (Kb of ethanol is 1.22 °C/m)
The boiling point of pure ethanol (C₂H₂OH, MM = 46.07 g/mol) is 78.4 °C. A solution is made using 100.0 g of ethanol (the solvent) and 24.1 g of glucose (MM = 180.16 g/mol). What is the boiling point of this solution, in °C? (Kb of ethanol is 1.22 °C/m)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![**Boiling Point Elevation of Ethanol Solution**
The boiling point of pure ethanol \((C_2H_5OH, \text{Molecular Mass} = 46.07 \ \text{g/mol})\) is 78.4°C. A solution is made by dissolving 24.1 g of glucose \((\text{Molecular Mass} = 180.16 \ \text{g/mol})\) in 100.0 g of ethanol (the solvent). What is the boiling point of this solution, in °C? The ebullioscopic constant \((K_b)\) of ethanol is 1.22 °C/m.
To find the boiling point of the solution, use the boiling point elevation formula:
\[ \Delta T_b = K_b \cdot m \]
where \( \Delta T_b \) is the boiling point elevation, \( K_b \) is the ebullioscopic constant, and \( m \) is the molality of the solution.
1. **Calculate the molality (m)**:
- Moles of glucose:
\[ \text{Moles of glucose} = \frac{\text{mass of glucose}}{\text{molar mass of glucose}} = \frac{24.1 \ \text{g}}{180.16 \ \text{g/mol}} \approx 0.1338 \ \text{mol} \]
- Mass of ethanol (in kg):
\[ \text{Mass of ethanol} = 100.0 \ \text{g} = 0.100 \ \text{kg} \]
- Molality:
\[ m = \frac{\text{moles of solute}}{\text{mass of solvent (in kg)}} = \frac{0.1338 \ \text{mol}}{0.100 \ \text{kg}} = 1.338 \ m \]
2. **Calculate the boiling point elevation (\(\Delta T_b\))**:
\[ \Delta T_b = K_b \cdot m = 1.22 \ \text{°C/m} \cdot 1.338 \ m \approx 1.632 \ \text{°C} \]
3. **Determine the new boiling point**:
\[ \text{Boiling point of solution} = \text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbc3b72c7-eb99-406f-83fe-82fc41b2a8b5%2F9669c553-e676-4ed4-baa8-300ff98a6a96%2Fzqjsvpg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Boiling Point Elevation of Ethanol Solution**
The boiling point of pure ethanol \((C_2H_5OH, \text{Molecular Mass} = 46.07 \ \text{g/mol})\) is 78.4°C. A solution is made by dissolving 24.1 g of glucose \((\text{Molecular Mass} = 180.16 \ \text{g/mol})\) in 100.0 g of ethanol (the solvent). What is the boiling point of this solution, in °C? The ebullioscopic constant \((K_b)\) of ethanol is 1.22 °C/m.
To find the boiling point of the solution, use the boiling point elevation formula:
\[ \Delta T_b = K_b \cdot m \]
where \( \Delta T_b \) is the boiling point elevation, \( K_b \) is the ebullioscopic constant, and \( m \) is the molality of the solution.
1. **Calculate the molality (m)**:
- Moles of glucose:
\[ \text{Moles of glucose} = \frac{\text{mass of glucose}}{\text{molar mass of glucose}} = \frac{24.1 \ \text{g}}{180.16 \ \text{g/mol}} \approx 0.1338 \ \text{mol} \]
- Mass of ethanol (in kg):
\[ \text{Mass of ethanol} = 100.0 \ \text{g} = 0.100 \ \text{kg} \]
- Molality:
\[ m = \frac{\text{moles of solute}}{\text{mass of solvent (in kg)}} = \frac{0.1338 \ \text{mol}}{0.100 \ \text{kg}} = 1.338 \ m \]
2. **Calculate the boiling point elevation (\(\Delta T_b\))**:
\[ \Delta T_b = K_b \cdot m = 1.22 \ \text{°C/m} \cdot 1.338 \ m \approx 1.632 \ \text{°C} \]
3. **Determine the new boiling point**:
\[ \text{Boiling point of solution} = \text
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning

Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education

Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning

Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education

Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning

Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY