The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:98.897.499.198.796.698.297.399Assume body temperatures of adults are normally distributed. Based on this data, find the 80% confidenceinterval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e.,parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population.80% C.I. =

Given that, the body temperatures in degrees Fahrenheit of a sample of adults in one small town are:…

Answered: The body temperatures in degrees…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A survey was conducted that asked 1016 people how many books they had read in the past year. Results indicated that x = 13.3 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and OB. There is 90% confidence that the population mean number of books read is between and OC. There is a 90% probability that the true mean number of books read is between and
Suppose that textbook weights are normally distributed. You measure 33 textbooks' weights, and find they have a mean weight of 61 ounces. Assume the population standard deviation is 13.2 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight. Round answers to 2 decimal places.
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 65 dates, the mean record high daily temperature in a certain city has a mean of 84.70°F. Assume the population standard deviation is 14.54°F.
You measure 38 textbooks' weights, and find they have a mean weight of 58 ounces. Assume the population standard deviation is 3.9 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight .
A poll was conducted that asked 1010 people how many books they had read in the past year. Results indicated that x= 10.5 books and s= 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Click the icon to view the table of areas under the t-distribution. Construct a 99% confidence interval for the mean number of books people read. (Use ascending order. Round to two decimal places as needed.)
Calculate the point estimate. An independent researcher wishes to estimate the average amount of money a young professional spends in buying coffee in Starbucks each month. A sample of 164 young professionals who are regular customers of Starbucks found the mean to be P3200. Assuming that the standard deviation of the population is P215. Find the 86% confidence interval of the population mean.
Find 90% confidence interval
Researchers studied the mean egg length (in millimeters) for a bird population. After taking a random sample of eggs, they obtained a 95% confidence interval of (45,60). What is the value of the margin of error? Choose the correct answer below. A. 15 mm B. 52.5 mm O c. 7.5 mm O D. 1.96
A poll was conducted that asked 1015 people how many books they had read in the past year. Results indicated that x= 14.3 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. E Click the icon to view the table of areas under the t-distribution, Construct a 90% confidence interval for the mean number of books people read. ) (Use ascending order. Round to two decimal places as needed.)
A survey was conducted that asked 1018 people how many books they had read in the past year. Results indicated that x = 14.3 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and OB. There is 90% confidence that the population mean number of books read is between OC. There is a 90% probability that the true mean number of books read is between and and
A survey was conducted that asked 1016 people how many books they had read in the past year. Results indicated that x = 11.8 books and s = 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Interpret the interval. E Click the icon to view the table of critical t-values. Construct a 99% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete vour choice. (Use ascending order. Round to two decimal places as needed.) O A. If repeated samples are taken, 99% of them will have a sample mean between and. Table of Critical t-Values O B. There is a 99% probability that the true mean number of books read is between and. OC. There is 99% confidence that the population mean number of books read is between and . t-Distribution Area in Right Tail Degrees of Freedom 0.25 0.20 0.15 0.10 0025 00 0.01 0.005 0.0025 0.001 0.0005 1.376 1.963 1.061 1.386 0.978 1.250…

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