The blood alcohol C2 H; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr*+ (aq) andcarbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 O,²) is orange in solution, and the Cr³* ion is green. The unbalanced redox equation isCr2 O,2 (aq) + C2H; OH(ag) → Cr³* (ag) + CO2 (g)If 40.35 mL of 0.0711 M potassium dichromate solution is required to titrate 27.5 g of blood plasma, determine the mass percent of alcohol in the blood.Mass percent

The question is based on calculation of mass percent of alcohol present in the blood sample. we have…

The blood alcohol C2 H5 OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 072) is orange in solution, and the Crt ion is green. The unbalanced redox equation is Cr2072 (ag) + С, H; ОН(ад) — Ст (ag) + CO2(9) If 40.35 mL of 0.0711 M potassium dichromate solution is required to titrate 27.5 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent =

The blood alcohol C2 H5 OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 072) is orange in solution, and the Crt ion is green. The unbalanced redox equation is Cr2072 (ag) + С, H; ОН(ад) — Ст (ag) + CO2(9) If 40.35 mL of 0.0711 M potassium dichromate solution is required to titrate 27.5 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The blood alcohol (C2H5OH) level can be determined bytitrating a sample of blood plasma with an acidic potassiumdichromate solution, resulting in the production of Cr31(aq)and carbon dioxide. The reaction can be monitored becausethe dichromate ion (Cr2O722) is orange in solution, and theCr31 ion is green. The unbalanced redox equation isCr2O722(aq) 1 C2H5OH(aq) n Cr31(aq) 1 CO2(g)If 31.05 mL of 0.0600 M potassium dichromate solution isrequired to titrate 30.0 g of blood plasma, determine the masspercent of alcohol in the blood.
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