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100. The blood alcobol (CH,OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr"(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr0) is orange in solution, and the Cr ion is green. The unbalanced redox equation is Cr,0,2 (ag) + C,H,OH(ag) Cr" (ag) + co.(e) If 31.05 ml. of 0.0600 M potassium dichromate solution is required to titrate 30.0 g of blood plasma, determine the mass percent of alcohol in the blood.

100. The blood alcobol (CH,OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr"(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr0) is orange in solution, and the Cr ion is green. The unbalanced redox equation is Cr,0,2 (ag) + C,H,OH(ag) Cr" (ag) + co.(e) If 31.05 ml. of 0.0600 M potassium dichromate solution is required to titrate 30.0 g of blood plasma, determine the mass percent of alcohol in the blood.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The blood alcohol (C2H5OH) level can be determined by
titrating a sample of blood plasma with an acidic potassium
dichromate solution, resulting in the production of Cr31(aq)
and carbon dioxide. The reaction can be monitored because
the dichromate ion (Cr2O7
22) is orange in solution, and the
Cr31 ion is green. The unbalanced redox equation is
Cr2O7
22(aq) 1 C2H5OH(aq) n Cr31(aq) 1 CO2(g)
If 31.05 mL of 0.0600 M potassium dichromate solution is
required to titrate 30.0 g of blood plasma, determine the mass
percent of alcohol in the blood.

100. The blood alcohol (CH,OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr"(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr07-) is orange in solution, and the Crt ion is green. The unbalanced redox equation is Cr,0,7-(ag) + CH,OH(ag) → Cr" (aq) + Co,g) If 31.05 ml. of 0.0600 M potassium dichromate solution is required to titrate 30.0 g of blood plasma, determine the mass percent of alcohol in the blood.
Transcribed Image Text:100. The blood alcohol (CH,OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr"(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr07-) is orange in solution, and the Crt ion is green. The unbalanced redox equation is Cr,0,7-(ag) + CH,OH(ag) → Cr" (aq) + Co,g) If 31.05 ml. of 0.0600 M potassium dichromate solution is required to titrate 30.0 g of blood plasma, determine the mass percent of alcohol in the blood.
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