(References) The blood alcohol CH; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion ( Cr2 O72) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2 (aq) + C,H;OH(aq) → Cr* (aq) + CO2(g) If 17.82 mL of 0.0666 M potassium dichromate solution is required to titrate 12.4 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent = Submit Answer Try Another Version 5 item attempts remaining

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The blood alcohol
CH; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of
Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (
Cr2 O72) is orange in solution, and the
Cr+ ion is green. The unbalanced redox equation is
Cr2O,2 (aq) + C,H;OH(aq) → Cr* (aq) + CO2(g)
If 17.82 mL of 0.0666 M potassium dichromate solution is required to titrate 12.4 g of blood plasma, determine the mass percent of alcohol in the blood.
Mass percent =
Submit Answer
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Transcribed Image Text:(References) The blood alcohol CH; OH level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion ( Cr2 O72) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2 (aq) + C,H;OH(aq) → Cr* (aq) + CO2(g) If 17.82 mL of 0.0666 M potassium dichromate solution is required to titrate 12.4 g of blood plasma, determine the mass percent of alcohol in the blood. Mass percent = Submit Answer Try Another Version 5 item attempts remaining
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