The block is at rest initial state. Then, 20 N force is applied to the block which has 2 kg mass. The friction coefficient of surface is 0.4. Determine the acceleration of the block when 20 N force is applied. F = 20 N 37° m = 2 kg k 0,4
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- An object of mass m is constrained to move on a horizontal frictionless circular track of radius m starts fIrom rest at time t = 0 and thereafter is puushed by an external force with constant magnitude F, always horizontal and tangent to the track. The horizontal component of the force exerted by the track on the object is given by А. О В. F C. Ft/mR D. Ft2/mR E. F/mg ans: DThe 8-kg block A is attached to link AC and rests on the 12-kg block B. Knowing that the coefficient of static friction is 0.2 between all surfaces of contact and neglecting the mass of the link. с OA B Draw the FBD(s) for block A and block B. -50 NDetermine the minimum value of weight W which may be applied without causing the 50-lb block to slip. The coefficient of static friction between the block and the plane is µ; = 0.2, and between the rope and the drum D µ3 = 0.3. W 45°
- F(t) Force_Crate Known values: Mass of Block 68 kg TT Hs μk 0 0.63 0.53 26° Problem Statement: A crate is initially at rest on a sloped surface, when a force is applied: F(t) where t is in seconds. Answers: When t=44.47 seconds, the crate has not yet started moving. Find the magnitude of the friction force at that time: 317.771 N The direction of the friction force at that time is: down the slope Find the time required for the crate to start moving: Find the crate's speed when t=174.9 s: 9.485 m/s Be sure to include units with your answers. 169.756 S 240+0.2 N,Now the block on the table has friction. Calculate the frictional force if the block is stationary. m = 8 kg M = 2.8 kg μs = 0.5 μk = 0.4A constant force Fa pushes a 22.5-kg box across a rough horizontal surface. The magnitude of Fa is 185 N and the force is inclined at an angle of θ = 30.0° below the horizontal. The coefficient of kinetic friction between the box and the surface is μk = 0.500. What is the magnitude of the box's acceleration?
- Continuing from problem 8, the force F is increased to 50 N. The data are as follows: a) The object's mass is 4 kg, b) g = 10 m/s². c) Coefficient of the kinetic friction = 0.5 / sqrt(3) and coefficient of the static friction = 1 / sqrt(3). d) Magnitude of the force F = 50 N. 30⁰ F What is the acceleration of the object in m/s²? Round to the nearest decimal.A 150-lb block rests on a horizontal surface. The coefficient of static and kinetic frictions between the block and the surface are 0.30 and 0.20, respectively. What is the acceleration of the block when P = 90 lb. P μs=0.30, μk=0.20 150 lbAn object with a mass of 4kg lies on a rough plane inclined at 20 degrees to horizontal. A force of 35N is applied parallel and up the plane. The object accelerates at 2.5m/s^2. What is the Uk between the object and plane
- Blocks A and B each have a mass m = 15 kg. The coefficient of static friction between A and B is μg = 0.28. The angle shown is 0 = 47°. Neglect any friction between B and C. A B P C Determine the largest horizontal force P that can be applied so that A will not slip on B. P= number (rtol=0.05, atol=1e-08) NThe 118-lb force P is applied to the 250-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate. The friction force is positive if to the right, negative if to the left. Assume ??= 0.48, ??= 0.38.