The block in the figure below has a mass m. The coefficient of static friction between the block and the inclined surface is ug. Determine the smallestmagnitude force P to prevent motion.Take: m = 80 kg, e = 30°, a = 20° and us = 0.20.P= 294.36 NP= 460.48 NP= 392.40 NP= 376.18 NP= 250.28 N

We have determine Smallest magnitude force

The block in the figure below has a mass m. The coefficient of static friction between the block and the inclined surface is uç. Determine the smallest magnitude force P to prevent motion. Take: m = 80 kg, e = 30°, a = 20° and us 0.20. P= 294.36 N P= 460.48 N P= 392.40 N P= 376.18 N P= 250.28 N

The block in the figure below has a mass m. The coefficient of static friction between the block and the inclined surface is uç. Determine the smallest magnitude force P to prevent motion. Take: m = 80 kg, e = 30°, a = 20° and us 0.20. P= 294.36 N P= 460.48 N P= 392.40 N P= 376.18 N P= 250.28 N

Elements Of Electromagnetics

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Author:Sadiku, Matthew N. O.

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

The block in the figure below has a mass m. The coefficient of static friction between the block and the inclined surface is ug. Determine the smallest
magnitude force P to prevent motion.
Take: m = 80 kg, e = 30°, a = 20° and us = 0.20.
P= 294.36 N
P= 460.48 N
P= 392.40 N
P= 376.18 N
P= 250.28 N

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