The bearing of the back tangent of a simple curve is N 70° E while the forward tangent has a bearing of S 82° 20' E. The degree of curve is 4.5°. Stationing of PC is at 10 + 345.43. It is proposed to decrease the central angle by changing the direction of the forward tangent by an angle of 7°, in such a way that the position of the PT forward tangent and the direction )ffice 365 hat -I.P. Manila Library. /ideo Presentation of the back tangent shall remain unchanged. 1. Compute the new angle of intersection 2. Compute the new radius of the curve 3. Compute the stationing of new PC
The bearing of the back tangent of a simple curve is N 70° E while the forward tangent has a bearing of S 82° 20' E. The degree of curve is 4.5°. Stationing of PC is at 10 + 345.43. It is proposed to decrease the central angle by changing the direction of the forward tangent by an angle of 7°, in such a way that the position of the PT forward tangent and the direction )ffice 365 hat -I.P. Manila Library. /ideo Presentation of the back tangent shall remain unchanged. 1. Compute the new angle of intersection 2. Compute the new radius of the curve 3. Compute the stationing of new PC
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The bearing of the back tangent of a simple curve is N 70° E while the forward tangent has a bearing of S 82° 20' E. The
degree of curve is 4.5°. Stationing of PC is at 10 + 345.43. It is proposed to decrease the central angle by changing the
direction of the forward tangent by an angle of 7°, in such a way that the position of the PT forward tangent and the direction
)ffice 365
hat
-I.P. Manila Library.
/ideo Presentation
of the back tangent shall remain unchanged.
1. Compute the new angle of intersection
2. Compute the new radius of the curve
3. Compute the stationing of new PC
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