1. In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270 90 hB (6+721) (6+421)A Poc 270 meters and BV=90 m. The P.T stationing of A is 6+421 and that of B is 6+721. Point A is along the P.C tangent passing through the PC while point B is along the tangent passing through the PT. The PCC is along line AB. Compute for the length of the radii for both curves.
1. In a compound curve, the line connecting the PI at point V and the PCC is an angle bisector. AV is 270 90 hB (6+721) (6+421)A Poc 270 meters and BV=90 m. The P.T stationing of A is 6+421 and that of B is 6+721. Point A is along the P.C tangent passing through the PC while point B is along the tangent passing through the PT. The PCC is along line AB. Compute for the length of the radii for both curves.
Chapter6: Deflections Of Beams: Geometric Methods
Section: Chapter Questions
Problem 1P
Related questions
Question
![1. In a compound curve, the line
connecting the PI at point V and
the PCC is an angle bisector. AV is
270
90
LB (6+721)
(6+421) A
270 meters and BV=90 m. The
P.T.
stationing of A is 6+421 and that
of B is 6+721. Point A is along the
tangent passing through the PC
while point B is along the tangent
P.C
passing through the PT. The PCC
is along line AB. Compute for the
length of the radii for both curves.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2006454-f2af-47dd-a56e-99be21b72fbe%2F69a32b8e-3526-4b34-a2b4-14b53b7f765a%2Fjcy21x_processed.png&w=3840&q=75)
Transcribed Image Text:1. In a compound curve, the line
connecting the PI at point V and
the PCC is an angle bisector. AV is
270
90
LB (6+721)
(6+421) A
270 meters and BV=90 m. The
P.T.
stationing of A is 6+421 and that
of B is 6+721. Point A is along the
tangent passing through the PC
while point B is along the tangent
P.C
passing through the PT. The PCC
is along line AB. Compute for the
length of the radii for both curves.
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