The beam section below has 4 #7 bars arranged in one row as shown below. The beam has normal-weight concrete with a compressive strength, f, equal to 4,000 psi, and the yield strength of thereinforcing steel is 60 ksi (Grade 60).14 in.3 in.3 in.164#7 bars21 in.4 in.15 in.5 in.(a) Determine M₁, the nominal moment capacity of the beam.n(b) Consider that the section has four #9 tension bars instead of four #7. In addition, it has four#4 bars in the top flange. The centroid of the top bars is 2.5 in. from the top edge of thebeam. Determine M₁, the nominal moment capacity of the beam, taking into account ofthe compression steel.

f'c=4000 psify=60,000 psiCase-ITo determine nominal moment capacity of beamCase-IITo determine…

The beam section below has 4 #7 bars arranged in one row as shown below. The beam has normal- weight concrete with a compressive strength, f, equal to 4,000 psi, and the yield strength of the reinforcing steel is 60 ksi (Grade 60).

The beam section below has 4 #7 bars arranged in one row as shown below. The beam has normal- weight concrete with a compressive strength, f, equal to 4,000 psi, and the yield strength of the reinforcing steel is 60 ksi (Grade 60).

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

The beam section below has 4 #7 bars arranged in one row as shown below. The beam has normal-
weight concrete with a compressive strength, f, equal to 4,000 psi, and the yield strength of the
reinforcing steel is 60 ksi (Grade 60).
14 in.
3 in.
3 in.
164
#7 bars
21 in.
4 in.
15 in.
5 in.
(a) Determine M₁, the nominal moment capacity of the beam.
n
(b) Consider that the section has four #9 tension bars instead of four #7. In addition, it has four
#4 bars in the top flange. The centroid of the top bars is 2.5 in. from the top edge of the
beam. Determine M₁, the nominal moment capacity of the beam, taking into account of
the compression steel.

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As a design engineer you are asked to peer review the design done by another engineer at your organization. A typical reinforced concrete floor slab plan is given. Assume all members to be simply supported. The specified compressive strength of concrete is 5000 psi and Grade-60 steel is used. Unit weight of concrete can be assumed as 150 lb/ft³. B 30'-0"- B2 -EQ.- EQ. -EQ. SEC 1 -40'-0" IS B1 B3 B3 B1 2 The only dead load acting on the slab is the self-weight of the members. The live load on the slab is 100 psf. Initial cross-section and reinforcement details of beam B1 is shown. Area of steel is 4.8in². EQ. 40'-0" B EQ. North
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5) Which of the following statements is true for design properties of non pre-stressed steel reinforcement as per NSCP 2015? A. For non-prestressed bars and wires, fy shall be Es times steel strain for any value of strain. B. For tensile steel strains greater than that corresponding to fy, stress shall be Es times steel strain. C. For non-prestressed bars and wires, the stress beyond fy shall be Es times steel strain. D. For tensile steel strains greater than that corresponding to fy, stress shall be considered independent of strain and equal to fy.
Give me right solution
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please answer step by step
Quèstion 2 Which of the following statements is not true for design properties of non pre-stressed steel reinforcement as per NSCP 2015? O A. For non-prestressed bars and wires, fy shall be Es times steel strain for any value of strain. O B. For tensile steel strains less than that corresponding to fy, stress shall be Es times steel strain. O. Steel yield strain is yield strength divided by modulus of elasticity. O D. For tensile steel strains greater than that corresponding to fy, stress shall be considered independent of strain and equal to fy.
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Hope your help concrete design (CE410) thanks
Asiacell lln. H.W. No.1 For the simply supported solid one way reinforced concrete slab shown in the figure below having a span of (L= 4m), check the following requirements using strength method: a- Slab thickness b- The spacing between reinforcement for main and shrinkage reinforcement c- The actual reinforcement with minimum reinforcement d- Calculate ultimate resisted moment that can be withstand by the slab e- Determine the ultimate uniformly distributed load carried by slab. f = 25 N/mm2 fy=420 N/mm² + 10mm@s00mm shrinkage h=200mm -L=4m- $12mm@200mm main