2. The axially loaded bar ABCD shown in figure 2 is held between 2 rigid supports. Thebar has cross-sectional area of A¡ from A to C and 2A¡ from C to D. (Take A1=100mm? , L= 200mm , P=5kN)241CD'Fig 2: Axially loaded bara. Derive formulas for RA and Rp :values using the given datab. Determine the displacements dB and dc at points B and Cc. Draw a diagram in which abscissa is distance from left hand support and ordinateis horizontal displacement at the pointthe ends of the bar and then find the numerical

The free-body diagram of the given axial bar can be drawn as below, Here, RA and RD are the…

Answered: The axially loaded bar ABCD shown in…

The axially loaded bar ABCD shown in figure 2 is held between 2 rigid supports. The bar has cross-sectional area of A¡ from A to C and 2A¡ from C to D. (Take A1= 100mm² , L= 200mm , P=5kN)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

2. The axially loaded bar ABCD shown in figure 2 is held between 2 rigid supports. The
bar has cross-sectional area of A¡ from A to C and 2A¡ from C to D. (Take A1=
100mm? , L= 200mm , P=5kN)
241
C
D'
Fig 2: Axially loaded bar
a. Derive formulas for RA and Rp :
values using the given data
b. Determine the displacements dB and dc at points B and C
c. Draw a diagram in which abscissa is distance from left hand support and ordinate
is horizontal displacement at the point
the ends of the bar and then find the numerical

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