The average return for large-cap domestic stock funds over the three years 2009-2011 was 14.4%.† Assume the three-year returns were normally distributed acro: with a standard deviation of 4.4%. (a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18%? (b) What is the probability an individual large-cap domestic stock fund had a three-year return of 15% or less? (c) How big does the return have to be to put a domestic stock fund in the top 20% for the three-year period? Step 1 (a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18%? It is given that the average return for large-cap domestic stock funds over a three-year time span was 14.4% with a standard deviation of 4.4%. Let x represent an individual large-cap domestic stock fund. The probability that this is at least 18% results in the probability statement P(x >✔ Step 2 Before finding this probability, the random variable x needs to be converted to the normal random variable z so that a table of probabilities can be used. Recall the 1 to convert an x value to the normal random variable, z, where x is the value that needs to be converted, u is the population mean, and is the population standard. deviation. z = The mean was given to be 14.4% and the standard deviation was given to be 4.4%. Find the value of the z-statistic corresponding to x = 18, rounding the result to decimal places. = = x-μ J 18 14.4 0.818✔✔ x-μ 4.4 Z 0.82 Thus, the new probability statement using the normal random variable z is P(Z > 0.818 ✔ 14.4 0.00 Step 3 The probability statement was determined to be P(z ≥ 0.82). Recall that the normal probability table below gives the area under the curve to the left of a given z-va the entire area under this curve is 1. Here, we want the area to the right of z = 0.82, so we can subtract the area to the left of z = 0.82 from 1. 0.01 0.02 = 0.2061 ✔ 0.03 0.04 0.05 0.7939 0.06 0.2061 0.82 ). 0.07 0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 0.08 ≥ 18). 0.09 Use the table excerpt above to find the probability that an individual large-cap domestic stock fund has a three-year return of at least 18%, rounding to four decima P(Z ≥ 0.82) = 1 - 0.7939 0.8106 0.8133

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question
The average return for large-cap domestic stock funds over the three years 2009-2011 was 14.4%.† Assume the three-year returns were normally distributed acros
with a standard deviation of 4.4%.
(a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18% ?
(b) What is the probability an individual large-cap domestic stock fund had a three-year return of 15% or less?
(c) How big does the return have to be to put a domestic stock fund in the top 20% for the three-year period?
Step 1
(a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18%?
It is given that the average return for large-cap domestic stock funds over a three-year time span was 14.4% with a standard deviation of 4.4%.
Let x represent an individual large-cap domestic stock fund. The probability that this is at least 18% results in the probability statement P(x > ✔
Step 2
Before finding this probability, the random variable x needs to be converted to the normal random variable z so that a table of probabilities can be used. Recall the fo
to convert an x value to the normal random variable, z, where x is the value that needs to be converted, u is the population mean, and is the population standard
deviation.
Z z =
The mean was given to be 14.4% and the standard deviation was given to be 4.4%. Find the value of the z-statistic corresponding to x = 18, rounding the result to
decimal places.
=
z
Z = X - H
o
x-μ
J
18 14.4
0.818 ✔
4.4
0.82
Thus, the new probability statement using the normal random variable z is P(Z > 0.818 ✔
Z
14.4
=
Step 3
The probability statement was determined to be P(z≥ 0.82). Recall that the normal probability table below gives the area under the curve to the left of a given z-val
the entire area under this curve is 1. Here, we want the area to the right of z = 0.82, so we can subtract the area to the left of z = 0.82 from 1.
0.00
0.02 0.03
0.07 0.08
0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852
0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133
0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389
0.01
0.04
0.7939
0.2061
0.82 ).
0.05
0.06
≥ 18).
0.09
Use the table excerpt above to find the probability that an individual large-cap domestic stock fund has a three-year return of at least 18%, rounding to four decimal
P(Z ≥ 0.82) 1-0.7939✔✔
0.2061✔
Transcribed Image Text:The average return for large-cap domestic stock funds over the three years 2009-2011 was 14.4%.† Assume the three-year returns were normally distributed acros with a standard deviation of 4.4%. (a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18% ? (b) What is the probability an individual large-cap domestic stock fund had a three-year return of 15% or less? (c) How big does the return have to be to put a domestic stock fund in the top 20% for the three-year period? Step 1 (a) What is the probability an individual large-cap domestic stock fund had a three-year return of at least 18%? It is given that the average return for large-cap domestic stock funds over a three-year time span was 14.4% with a standard deviation of 4.4%. Let x represent an individual large-cap domestic stock fund. The probability that this is at least 18% results in the probability statement P(x > ✔ Step 2 Before finding this probability, the random variable x needs to be converted to the normal random variable z so that a table of probabilities can be used. Recall the fo to convert an x value to the normal random variable, z, where x is the value that needs to be converted, u is the population mean, and is the population standard deviation. Z z = The mean was given to be 14.4% and the standard deviation was given to be 4.4%. Find the value of the z-statistic corresponding to x = 18, rounding the result to decimal places. = z Z = X - H o x-μ J 18 14.4 0.818 ✔ 4.4 0.82 Thus, the new probability statement using the normal random variable z is P(Z > 0.818 ✔ Z 14.4 = Step 3 The probability statement was determined to be P(z≥ 0.82). Recall that the normal probability table below gives the area under the curve to the left of a given z-val the entire area under this curve is 1. Here, we want the area to the right of z = 0.82, so we can subtract the area to the left of z = 0.82 from 1. 0.00 0.02 0.03 0.07 0.08 0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 0.01 0.04 0.7939 0.2061 0.82 ). 0.05 0.06 ≥ 18). 0.09 Use the table excerpt above to find the probability that an individual large-cap domestic stock fund has a three-year return of at least 18%, rounding to four decimal P(Z ≥ 0.82) 1-0.7939✔✔ 0.2061✔
Step 7
Use the above table to find the probability of completing the exam in an hour or less, P(z ≤ 0.14), rounding the result to four decimal places.
P(Z ≤ 0.14) = 0.5557✔
0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279
0.1 0.5398 0.5438
0.5319 0.5359
0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753
0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141
probability =
(c) How big does the return have to be to put a domestic stock fund in the top 20% for the three-year period?
Another way to think about this question is in terms of probability instead of percentage. To have a domestic stock fund in the top 20% means that 80% of domestic stock
funds will be less than some value. First convert 80% to a probability.
percentage
100%
0.8 ✔
x = 20 + u
100%
0.5557
Here, we are working backwards to find a return such that if new large-cap domestic stock fund was randomly selected the probability the new fund has a return less than
this value is 0.8✔✔
Step 8
Recall that the standard normal random variable z represents the number of standard deviations a value x is away from the mean. The normal probability table gives area
under the curve to the left of a given z-value, also called the cumulative probability.
Use the table to find the value of zo corresponding to a 0.80 cumulative probability, rounding the result to two decimal places.
P(Z = z) = 0.80
Zo
x-μ
80 %
0.80
0.84✔ 0.84
Step 9
The z-value corresponding to a 0.80 cumulative probability was found to be 0.84. Thus, the necessary return x will be 0.84 standard deviations above the mean return.
Recall the formula to convert a given value x to the standard normal random z.
= 0.84(4.4) +
X
0.80.
Here, we have the values of z, μ, and o, but need to find x. Solve the equation for x.
x = 0.84
Therefore, a return of
Step 10
The z value that corresponds to a probability of 0.80 was found to be 0.84, the mean was given to be μ = 14.4%, and the standard deviation was given to be o = 4.4%.
Substitute these values into the formula derived to calculate x, rounding to two decimal places.
μ+oz
Submit Skip (you cannot come back)
% or higher will put a domestic stock fund in the top 20%.
Transcribed Image Text:Step 7 Use the above table to find the probability of completing the exam in an hour or less, P(z ≤ 0.14), rounding the result to four decimal places. P(Z ≤ 0.14) = 0.5557✔ 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.1 0.5398 0.5438 0.5319 0.5359 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 probability = (c) How big does the return have to be to put a domestic stock fund in the top 20% for the three-year period? Another way to think about this question is in terms of probability instead of percentage. To have a domestic stock fund in the top 20% means that 80% of domestic stock funds will be less than some value. First convert 80% to a probability. percentage 100% 0.8 ✔ x = 20 + u 100% 0.5557 Here, we are working backwards to find a return such that if new large-cap domestic stock fund was randomly selected the probability the new fund has a return less than this value is 0.8✔✔ Step 8 Recall that the standard normal random variable z represents the number of standard deviations a value x is away from the mean. The normal probability table gives area under the curve to the left of a given z-value, also called the cumulative probability. Use the table to find the value of zo corresponding to a 0.80 cumulative probability, rounding the result to two decimal places. P(Z = z) = 0.80 Zo x-μ 80 % 0.80 0.84✔ 0.84 Step 9 The z-value corresponding to a 0.80 cumulative probability was found to be 0.84. Thus, the necessary return x will be 0.84 standard deviations above the mean return. Recall the formula to convert a given value x to the standard normal random z. = 0.84(4.4) + X 0.80. Here, we have the values of z, μ, and o, but need to find x. Solve the equation for x. x = 0.84 Therefore, a return of Step 10 The z value that corresponds to a probability of 0.80 was found to be 0.84, the mean was given to be μ = 14.4%, and the standard deviation was given to be o = 4.4%. Substitute these values into the formula derived to calculate x, rounding to two decimal places. μ+oz Submit Skip (you cannot come back) % or higher will put a domestic stock fund in the top 20%.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman