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- Who misses work more often at the ABC Company: Smokers or non-smokers? Are they different? Test at .02 significance level. Smokers: Average number of days absent = 12; standard deviation = 5.0; n = 60Non-Smokers: Average number of days absent = 9; standard deviation = 4.0; n = 40;5. Inferential Statistics - Hypothesis Testing Historically, evening long-distance calls from a particular city have averaged 15.4 minutes per call. In a random sample of 56 calls, the sample mean time was 17.3 minutes. Assume the population standard deviation is 5 minutes. Using a 0.05 level of significance, is there sufficient evidence to conclude that the average evening long-distance call has increased?A manufacturer claims that only 2% of their products are defective. A store receives a delivery of 300 items from the manufacturer. Let p-hat = the proportion of defective items in a sample of 300 items. Assuming the manufacturer is correct that only 2% of their products are defective, what are the mean and standard deviation of the sampling distribution of p-hat ? Options: The mean is 0.02 and the standard deviation is 0.008. The mean is 6 and the standard deviation is 2.42. The mean is 6 and the standard deviation is 5.88. The mean is 0.02 and the standard deviation is 0.196.
- The average retirement age in America is 63 years old. Do small business owners retire at a different average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 66, 60, 62, 71, 58, 73, 60, 72, 70, 61, 57 What can be concluded at the the a 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: uv = 63 H: uv> c. The test statistic ? = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that O The data suggest the population mean retirement age for small business owners is not significantly different from 63 at a = 0.05, so there is insufficient evidence to conclude that the population mean…12. The manager of a rent-a-car business want to know whether the true average numbers of cars rented a day is 25 with a standard deviation of 6.9 rentals. A random sample of 36 days was taken and found to have an average of 22.8 rentals. Test at 0.05 level of significance. Criterion : Decision : Conclusion :Nutrition Iron-deficiency anemia is an important nutritional health problem in the United States. A dietary assessment was performed on 56 boys 9 to 11 years of age whose families were below the poverty level. The mean daily iron intake among these boys was found to be 12.40 mg with standard deviation 4.71 mg. Suppose the mean daily iron intake among a large population of 9- to 11-year-old boys from all income strata is 14.41 mg. We want to test whether the mean iron intake among the low-income group is different from that of the general population. You can use the Inferential Statistics page and the Distribution Calculators page in SALT to answer parts of this question. (a) State the hypotheses (in mg) that we can use to consider this question. (Enter != for as needed.) Ho: H₁: (b) Carry out the hypothesis test in part (a) using the critical-value method with an a level of 0.05, and summarize your findings. Find the test statistic. (Round your answer to two decimal places.) Find the…
- i need C and DIn an effort to determine which company between Primacom Outsourcing Company and Technica Global Services has better customer service, an independent survey group gathered data on the length of time (in minutes) a customer has to wait on hold before someone answers the phone when calling the customer care hotline for assistance. The data is summarized below. Statistics Primacom Outsourcing Company Technica Global Services Mean 8.14 9.426 Standard Deviation 1.345 1.813 Sample Size 7 7 Is there a significant difference between the average lengths of time customers are on hold for the two companies? Use a 5% level of significance. Assume that the lengths of time on hold are normally distributed with unknown but equal population variances. A. Perform a complete test of hypothesis. B. Select here the conclusion for this test of hypothesis. There is a significant difference between the average lengths of time customers are on hold for the two companies. There is no significant difference…Dr. Graham is interested in determining if middle-aged adults use text messaging more or less frequently than the general population. Dr. Graham collects information on text messaging from a random sample of 50 adults ages 25 to 44. Dr. Graham finds that these individuals send or receive an average of 68 text messages per day. Using the population mean (and standard deviation) of 41.5 texts per day (34 texts per day), determine whether adults in this age group use text messaging more than the general public.
- A . please do not uplod handwritting image ( only typing please)The following are the normalized levels of a critical protein in 12 samples of blood: 8.2 , 4.7 , 10.3 , 11.7 , 18.3 , 5.9 , 3.8 , 18.9 , 7.6 , 14.2 , 9.8 , 16.4 Compute the sample mean, the sample median, and the sample standard deviation.The state of Connecticut claims that the average time on death row is 15 years. A random survey of 75 death row inmates revealed that the average length of time on death row is 17.8 years with a standard deviation of 6.8 years. Conduct a hypothesis to test the state of Connecticut's claim. Use 5% significance level. What type of test should be run? t-test of a mean z-test of a proportion The alternative hypothesis indicates a right-tailed test left-tailed test two-tailed test Calculate the p-value. Round to 4 decimal places. What is the decision? We fail to reject the claim that the average time on death row is 15 years We reject the claim that the average time on death row is 15 years