College tuition: The mean annual tuition and fees in the 2013-2014 academic year for a sample of 13 private colleges in California was $38,000 with a standard deviation of $7900. A dotplot shows that it is reasonable to assume that the population is approximately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,000 Use the a 0.01 level of significance and the P-value method with the TI-84 Plus calculator.
College tuition: The mean annual tuition and fees in the 2013-2014 academic year for a sample of 13 private colleges in California was $38,000 with a standard deviation of $7900. A dotplot shows that it is reasonable to assume that the population is approximately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,000 Use the a 0.01 level of significance and the P-value method with the TI-84 Plus calculator.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 1GP
Related questions
Question
Watching TV: In 2012, the General Social Survey asked a sample of 1320 people how much time they spent watching TV each
day. The mean number of hours was 2.85 with a standard deviation of 2.65. A sociologist claims that people watch a mean of 3
hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day differs from
the claim? Use the a =0.05 level of significance and the P-value method with the TI-84 Plus calculator.

Transcribed Image Text:College tuition: The mean annual tuition and fees in the 2013-2014 academic year for a sample of 13 private colleges in
California was $38,000 with a standard deviation of $7900. A dotplot shows that it is reasonable to assume that the population is
approximately normal. Can you conclude that the mean tuition and fees for private institutions in California differs from $35,0007
Use the a = 0.01 level of significance and the P-value method with the TI-84 Plus calculator.
Part: 0/4
Part 1 of 4
State the appropriate null and alternate hypotheses.
D-O
This hypothesis test is a (Choose one)
test.
left-tailed
right-talled
two-taled
Part 2 of 4
Compute the P-value. Round the P-value to at least four decimal places.
P-value =
Part 3 of 4
Determine whether to reject H
(Choose one)
the null hypothesis Ho-
Reject
Do not reject

Transcribed Image Text:Watching TV: In 2012, the General Social Survey asked a sample of 1320 people how much time they spent watching TV each
day. The mean number of hours was 2.85 with a standard deviation of 2.65. A sociologist claims that people watch a mean of 3
hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day differs from
the claim? Use the a=0.05 level of significance and the P-value method with the TI-84 Plus calculator.
Part: 0 / 4
Part 1 of 4
(a) State the appropriate null and alternate hypotheses.
O<O
ロ=ロ
H:
ロ=ロ
This hypothesis test is a (Choose one) ▼
test.
left-tailed
right-tailed
two-tailed
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