Can someone please help? Thank you. 2) A company wants to determine whether a new training program improves employee productivity. Before thetraining, the average productivity score was 120. After the training, a random sample of 30 employees had anaverage score of 130 with a standard deviation of 15. Can the company conclude that the training program iseffective at a significance level of 0.05?

Answered: 2) A company wants to determine whether…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Can someone please help? Thank you.

2) A company wants to determine whether a new training program improves employee productivity. Before the
training, the average productivity score was 120. After the training, a random sample of 30 employees had an
average score of 130 with a standard deviation of 15. Can the company conclude that the training program is
effective at a significance level of 0.05?

Expert Solution

Step 1: Formula Used

Here we can use t- distribution to check the validity of the statement. In this method first we set up null and alternate hypothesis and then calculate test statistics using the following formula

$t equals fraction numerator x with bar on top minus mu over denominator fraction numerator s over denominator square root of n end fraction end fraction h e r e space x with bar on top equals s a m p l e space m e a n mu equals p o p u l a t i o n space m e a n s equals s a m p l e space s d n equals s a m p l e space s i z e$

Now if the value of test statistics is greater than the critical value then we reject the null hypothesis or otherwise do not reject it.