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The arm in figure P8.7 weighs F = 41.5 N. The weight of the arm acts through point A as %3D shown. F, 12° F, 0.080 m -0.290 m P8.7 from Serway and Vuille 9th Ed. I60qsnoYEer gisB trom Newton's second Law for an object in to sequilibrium. You should A) Write down the two equations that come use the variables FrFel and F=1Fl in these equations.

The arm in figure P8.7 weighs F = 41.5 N. The weight of the arm acts through point A as %3D shown. F, 12° F, 0.080 m -0.290 m P8.7 from Serway and Vuille 9th Ed. I60qsnoYEer gisB trom Newton's second Law for an object in to sequilibrium. You should A) Write down the two equations that come use the variables FrFel and F=1Fl in these equations.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Title: Analyzing Forces in a Human Arm** **Description:** **Figure P8.7 Analysis** The diagram shows a human arm with forces acting on it. The arm's weight is given as \( F_g = 41.5 \, \text{N} \). This weight acts through point A on the arm. **Diagram Explanation:** - **Forces:** - \( F_t \): Tension force, directed along the arm at an angle \( \theta \). - \( F_s \): Stabilizing force at point O, perpendicular to the arm. - \( F_g \): Gravitational force acting downward through point A. - **Distances:** - From point O to where the force \( F_t \) is applied: \( 0.080 \, \text{m} \). - From point O to point A (where \( F_g \) acts): \( 0.290 \, \text{m} \). **Angle:** - The angle between the direction of \( F_t \) and the horizontal is \( \theta = 12^\circ \). **Task:** A) Write down the two equations that come from Newton’s second law for an object in equilibrium. Use the variables \( F_t \), \( F_s \), and \( F_g \) in these equations. **Reference:** - This content is based on P8.7 from Serway and Vuille, 9th Edition.
Transcribed Image Text:**Title: Analyzing Forces in a Human Arm** **Description:** **Figure P8.7 Analysis** The diagram shows a human arm with forces acting on it. The arm's weight is given as \( F_g = 41.5 \, \text{N} \). This weight acts through point A on the arm. **Diagram Explanation:** - **Forces:** - \( F_t \): Tension force, directed along the arm at an angle \( \theta \). - \( F_s \): Stabilizing force at point O, perpendicular to the arm. - \( F_g \): Gravitational force acting downward through point A. - **Distances:** - From point O to where the force \( F_t \) is applied: \( 0.080 \, \text{m} \). - From point O to point A (where \( F_g \) acts): \( 0.290 \, \text{m} \). **Angle:** - The angle between the direction of \( F_t \) and the horizontal is \( \theta = 12^\circ \). **Task:** A) Write down the two equations that come from Newton’s second law for an object in equilibrium. Use the variables \( F_t \), \( F_s \), and \( F_g \) in these equations. **Reference:** - This content is based on P8.7 from Serway and Vuille, 9th Edition.
**Text:** **B)** Because this arm is in equilibrium, you can pick any axis of rotation you would like. On the picture above identify an axis of rotation that reduces the number of unknowns in the torque equation you will create for part C). **C)** Write down the equation that results from the fact that the “Net external torque (for the axis you chose in part B) must be zero” on this arm. **Explanation:** The text above discusses the concepts of equilibrium and torque in physics. When an arm or object is in equilibrium, the sum of forces and the sum of torques acting on it must be zero. Part B involves selecting an axis of rotation, which is crucial for simplifying the torque equation by reducing unknowns. In Part C, the task is to formulate an equation where the net external torque about that axis is zero, reflecting the state of equilibrium.
Transcribed Image Text:**Text:** **B)** Because this arm is in equilibrium, you can pick any axis of rotation you would like. On the picture above identify an axis of rotation that reduces the number of unknowns in the torque equation you will create for part C). **C)** Write down the equation that results from the fact that the “Net external torque (for the axis you chose in part B) must be zero” on this arm. **Explanation:** The text above discusses the concepts of equilibrium and torque in physics. When an arm or object is in equilibrium, the sum of forces and the sum of torques acting on it must be zero. Part B involves selecting an axis of rotation, which is crucial for simplifying the torque equation by reducing unknowns. In Part C, the task is to formulate an equation where the net external torque about that axis is zero, reflecting the state of equilibrium.
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