Find T₁ The hanging sphere off the table has a mass of 2.98 kg. The string makes a 27.1° angle to the ceiling. How much does the sphere weigh? Find T₂ T₁ N N 8. N N The block on the table does not move. How much friction must be acting between the table and the block?

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Analysis

**Diagram Description:**
The diagram features a frictionless pulley system with a mass hanging off a table. There is a string connected to the mass (sphere), making an angle of 27.1° with the ceiling. There are two tension forces indicated: \( T_1 \) acting along the horizontal part of the string on the table, and \( T_2 \) acting along the string that makes an angle with the ceiling.

**Questions:**

1. **The hanging sphere off the table has a mass of 2.98 kg. The string makes a 27.1° angle to the ceiling.**

   - **How much does the sphere weigh?**  
     \[ \_\_\_\_ \, \text{N} \]

   - **Find \( T_1 \)**  
     \[ \_\_\_\_ \, \text{N} \]

   - **Find \( T_2 \)**  
     \[ \_\_\_\_ \, \text{N} \]

2. **The block on the table does not move. How much friction must be acting between the table and the block?**

   \[ \_\_\_\_ \, \text{N} \]

### Explanation:

- **Weight of the Sphere:**
  The weight of the sphere (\( W \)) is calculated using the formula \( W = mg \), where \( m \) is the mass of the sphere and \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).

- **Tension in the String:**
  \( T_1 \) and \( T_2 \) represent the tensions in the string. Using trigonometry and the fact that the system is in equilibrium, you can set up equations to solve for these tensions. The angle of 27.1° will be useful in resolving components of the tensions.

- **Frictional Force:**
  The frictional force (\( f \)) can be determined once the horizontal component of the tension is known (\( T_1 \)), as this must be equal to the frictional force since the block does not move.
Transcribed Image Text:### Problem Analysis **Diagram Description:** The diagram features a frictionless pulley system with a mass hanging off a table. There is a string connected to the mass (sphere), making an angle of 27.1° with the ceiling. There are two tension forces indicated: \( T_1 \) acting along the horizontal part of the string on the table, and \( T_2 \) acting along the string that makes an angle with the ceiling. **Questions:** 1. **The hanging sphere off the table has a mass of 2.98 kg. The string makes a 27.1° angle to the ceiling.** - **How much does the sphere weigh?** \[ \_\_\_\_ \, \text{N} \] - **Find \( T_1 \)** \[ \_\_\_\_ \, \text{N} \] - **Find \( T_2 \)** \[ \_\_\_\_ \, \text{N} \] 2. **The block on the table does not move. How much friction must be acting between the table and the block?** \[ \_\_\_\_ \, \text{N} \] ### Explanation: - **Weight of the Sphere:** The weight of the sphere (\( W \)) is calculated using the formula \( W = mg \), where \( m \) is the mass of the sphere and \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). - **Tension in the String:** \( T_1 \) and \( T_2 \) represent the tensions in the string. Using trigonometry and the fact that the system is in equilibrium, you can set up equations to solve for these tensions. The angle of 27.1° will be useful in resolving components of the tensions. - **Frictional Force:** The frictional force (\( f \)) can be determined once the horizontal component of the tension is known (\( T_1 \)), as this must be equal to the frictional force since the block does not move.
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