Given: X = 5t – 6t – 7t t = Isec and t, = 3 secs Required: Solve for a.) displacement, b.) average velocity c.) instantaneous velocities d.) average acceleration e.) instantaneous acceleration
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Hi, please help me solve this question. With clear or step-by-step solutions. I would really appreciate the help, willing to give a thumbs up and a review. Thank you!
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X= 5t' – 6t – 7t
t = 1sec and t; = 3 secs
Required:
Solve for
a.) displacement,
b.) average velocity
c.) instantaneous velocities
d.) average acceleration
e.) instantaneous acceleration"
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Step by step
Solved in 2 steps with 2 images
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- This is an awesome help to me but could I get a more in depth of steps on how to do these. I would really appreciate it.I have been trying to solve this question and keep getting wrong answers, I would really appreciate any help/explanation with correct answer to the following problem. ( 0.75 and 1.7 values are wrong )answers with solutions please!
- How can I find the graphs, solutions and answers to this problem? (answers should be rounded off to four decimal places)Please show clear steps! Trying to understand this type of problem. Thanks.I just want explanations like the equations I need to use because I'm not being taught how to solve these
- Help me with these set of questions. Please do provide a complete solution to justify the answers. Thank you.DUE NOW. Please answer it correctly and with complete solution. Please provide the solving in this format: Given, Required, Formula, Solution, and Answer. Please computerize or type the solutions digitally, not written in the paper. Thanks!This was wrong. Can you solve this again with these numbers? What is the root mean square velocity, vrms, for Hydrogen molecules (H2) at 20oC? Hint: How many amu does an H2 molecule contain. 1 amu = 1.67 x 10-27 kg Boltzman's Constant, k = 1.38 x 10-23 J/K Give your answer in m/s to 4 significant figures (NO DECIMALS)
- So is final answer 1/2 or 1/4. I'm confused regarding your final answer.e Get live help whenever you need from online tutors!Try bartleby tutor todayarrow_forward Oh no! Our expert couldn't answer your question. Don't worry! We won't leave you hanging. Plus, we're giving you back one question for the inconvenience. Here's what the expert had to say: Hi and thanks for your question! Unfortunately, it looks incomplete. Please resubmit the question with the figure. We've credited a question back to your account. Apologies for the inconvenience. Ask Your Question Again 25 of 30 questions left this cycle Renews on 1/18/21 Question The spring shown in the figure is compressed 80.0 cm and is used to launch a 82kg. physics student along a frictionless track, Given values are K= 85000 Nm and Height = 11m. What is the student’s speed (in m/s) just after losing contact with the spring? 2. What was the student’s speed (in m/s) at the bottom of the hill? 3. How far up the incline (in meters) does the student slide? Please use…Which one is the correct answer and please explain why. Thank you.