The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL c 0.125 M KCI with 0.500 M AgNO3 (Ksp.AgCI = 1.8 x 10-10). Calculate the cell potential at the following points a) 5.00 mL before Veg b) at Veg c) 5.00 mL after Veg + SCE Ag Half-cell reaction : Ag* + e → Ag E° = 0.799 3 V and potential of SCE is 0.241 V
The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL c 0.125 M KCI with 0.500 M AgNO3 (Ksp.AgCI = 1.8 x 10-10). Calculate the cell potential at the following points a) 5.00 mL before Veg b) at Veg c) 5.00 mL after Veg + SCE Ag Half-cell reaction : Ag* + e → Ag E° = 0.799 3 V and potential of SCE is 0.241 V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL of
0.125 M KCI with 0.500 M AgNO3 (Ksp,ARCI = 1.8 x 10-10). Calculate the cell potential at the following points:
a) 5.00 mL before Veg
b) at Veg
c) 5.00 mL after Veg
SCE
Ag
Half-cell reaction : Ag* + e → Ag
E° = 0.799 3 V and potential of SCE is 0.241 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9957079-28d0-4671-8313-36ecaf8113d3%2F826b489b-10b8-4eee-a14e-fcaa351050e7%2Fffr2bup_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The apparatus shown in the picture was used to measure the cell potential during the titration of 100.0 mL of
0.125 M KCI with 0.500 M AgNO3 (Ksp,ARCI = 1.8 x 10-10). Calculate the cell potential at the following points:
a) 5.00 mL before Veg
b) at Veg
c) 5.00 mL after Veg
SCE
Ag
Half-cell reaction : Ag* + e → Ag
E° = 0.799 3 V and potential of SCE is 0.241 V
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