50.0 mL of 0.100 M Co3+ solution is titrated with 35.00 mL of 0.130 M MnO42- solution. The potential is measured against the Ag-AgCl reference electrode. Find the measured cell potential. E0 (Ag/AgCl) = 0.197 V Co3+ + e- :left_right_arrow: Co2+ E0 = 1.92 V MnO4- + e- :left_right_arrow: MnO42- E0 = 0.56 V A. 0.425v B. 0.624V C. 1.664V D. 1.861V
50.0 mL of 0.100 M Co3+ solution is titrated with 35.00 mL of 0.130 M MnO42- solution. The potential is measured against the Ag-AgCl reference electrode. Find the measured cell potential. E0 (Ag/AgCl) = 0.197 V Co3+ + e- :left_right_arrow: Co2+ E0 = 1.92 V MnO4- + e- :left_right_arrow: MnO42- E0 = 0.56 V A. 0.425v B. 0.624V C. 1.664V D. 1.861V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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50.0 mL of 0.100 M Co3+ solution is titrated with 35.00 mL of 0.130 M MnO42- solution. The potential is measured against the Ag-AgCl reference electrode. Find the measured cell potential.
E0 (Ag/AgCl) = 0.197 V
Co3+ + e- :left_right_arrow: Co2+ E0 = 1.92 V
MnO4- + e- :left_right_arrow: MnO42- E0 = 0.56 V
A. 0.425v
B. 0.624V
C. 1.664V
D. 1.861V
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