Using the Nernst equation calculate the cell voltage for: Fe(s) + Cd²+(aq) → Fe2+(aq) + Cd(s) when the [Fe2+] = 0.19 M and [Cd2+] = 2.0 M. %3D Potentially useful information: Fe2+ + 2e- Fe(s); ɛ° = -0.44 V Cd(s); ɛ0 = -0.40 V Cd2+ + 2e- → %3D 0.12 Submit Answer Incorrect. Tries 7/99 Previous Tries

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Finding cell potential with the Nernst equation
Using the Nernst equation calculate the cell voltage for:
Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s)
when the [Fe?+] = 0.19 M and [Cd2+] = 2.0 M.
Potentially useful information:
Fe2+ + 2e-
Fe(s); ɛ0 = -0.44 V
Cd2+ + 2e- →
Cd(s); ɛº = -0.40 V
0.12
Submit Answer
Incorrect. Tries 7/99 Previous Tries
Transcribed Image Text:Using the Nernst equation calculate the cell voltage for: Fe(s) + Cd2+(aq) → Fe2+(aq) + Cd(s) when the [Fe?+] = 0.19 M and [Cd2+] = 2.0 M. Potentially useful information: Fe2+ + 2e- Fe(s); ɛ0 = -0.44 V Cd2+ + 2e- → Cd(s); ɛº = -0.40 V 0.12 Submit Answer Incorrect. Tries 7/99 Previous Tries
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