A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Instructions for Educational Exercise:**

1. **Calculate the Number of Moles of Electrons:**
   - Determine the quantity of moles of electrons that have passed through the circuit during the specified time period.
   - **[Input Box]**: Enter the calculated value for moles of electrons.

2. **Calculate the Mass Change in Grams of the Copper and Nickel Electrodes:**
   - Assess the change in mass for both copper and nickel electrodes in grams.
   - **Mass Change of Copper Electrode:**
     - **[Input Box]**: Enter the mass change of the copper electrode in grams.
   - **Mass Change of Nickel Electrode:**
     - **[Input Box]**: Enter the mass change of the nickel electrode in grams.
Transcribed Image Text:**Instructions for Educational Exercise:** 1. **Calculate the Number of Moles of Electrons:** - Determine the quantity of moles of electrons that have passed through the circuit during the specified time period. - **[Input Box]**: Enter the calculated value for moles of electrons. 2. **Calculate the Mass Change in Grams of the Copper and Nickel Electrodes:** - Assess the change in mass for both copper and nickel electrodes in grams. - **Mass Change of Copper Electrode:** - **[Input Box]**: Enter the mass change of the copper electrode in grams. - **Mass Change of Nickel Electrode:** - **[Input Box]**: Enter the mass change of the nickel electrode in grams.
**Text:**

A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.

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**Explanation:**

This text is a problem statement commonly found in physics courses related to electricity. The task is to calculate the amount of electric charge (Q) that flows through a circuit when a known current (I) flows over a specified time period (t). In this case, a current of 2.18 amperes (A) flows for 2.95 hours (h).

**Calculation:**

To solve the problem, we use the formula:

\[ Q = I \times t \]

Where:
- \( Q \) is the charge in coulombs (C),
- \( I \) is the current in amperes (A),
- \( t \) is the time in seconds (s).

First, convert the time from hours to seconds:

\[ 2.95 \, \text{hours} = 2.95 \times 3600 \, \text{seconds} \]

Calculate the charge:

\[ Q = 2.18 \, \text{A} \times 2.95 \times 3600 \, \text{s} \]

\[ Q = 2.18 \times 10620 \, \text{C} \]

\[ Q = \text{Calculate the final result for precise charge.} \]
Transcribed Image Text:**Text:** A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time. --- **Explanation:** This text is a problem statement commonly found in physics courses related to electricity. The task is to calculate the amount of electric charge (Q) that flows through a circuit when a known current (I) flows over a specified time period (t). In this case, a current of 2.18 amperes (A) flows for 2.95 hours (h). **Calculation:** To solve the problem, we use the formula: \[ Q = I \times t \] Where: - \( Q \) is the charge in coulombs (C), - \( I \) is the current in amperes (A), - \( t \) is the time in seconds (s). First, convert the time from hours to seconds: \[ 2.95 \, \text{hours} = 2.95 \times 3600 \, \text{seconds} \] Calculate the charge: \[ Q = 2.18 \, \text{A} \times 2.95 \times 3600 \, \text{s} \] \[ Q = 2.18 \times 10620 \, \text{C} \] \[ Q = \text{Calculate the final result for precise charge.} \]
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