A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.
A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Instructions for Educational Exercise:**
1. **Calculate the Number of Moles of Electrons:**
- Determine the quantity of moles of electrons that have passed through the circuit during the specified time period.
- **[Input Box]**: Enter the calculated value for moles of electrons.
2. **Calculate the Mass Change in Grams of the Copper and Nickel Electrodes:**
- Assess the change in mass for both copper and nickel electrodes in grams.
- **Mass Change of Copper Electrode:**
- **[Input Box]**: Enter the mass change of the copper electrode in grams.
- **Mass Change of Nickel Electrode:**
- **[Input Box]**: Enter the mass change of the nickel electrode in grams.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fedbef1-4110-4bb3-9906-fd5663476380%2F871408da-4a57-43b1-a053-92a6a7f8210f%2F2ds0war_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Instructions for Educational Exercise:**
1. **Calculate the Number of Moles of Electrons:**
- Determine the quantity of moles of electrons that have passed through the circuit during the specified time period.
- **[Input Box]**: Enter the calculated value for moles of electrons.
2. **Calculate the Mass Change in Grams of the Copper and Nickel Electrodes:**
- Assess the change in mass for both copper and nickel electrodes in grams.
- **Mass Change of Copper Electrode:**
- **[Input Box]**: Enter the mass change of the copper electrode in grams.
- **Mass Change of Nickel Electrode:**
- **[Input Box]**: Enter the mass change of the nickel electrode in grams.
![**Text:**
A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.
---
**Explanation:**
This text is a problem statement commonly found in physics courses related to electricity. The task is to calculate the amount of electric charge (Q) that flows through a circuit when a known current (I) flows over a specified time period (t). In this case, a current of 2.18 amperes (A) flows for 2.95 hours (h).
**Calculation:**
To solve the problem, we use the formula:
\[ Q = I \times t \]
Where:
- \( Q \) is the charge in coulombs (C),
- \( I \) is the current in amperes (A),
- \( t \) is the time in seconds (s).
First, convert the time from hours to seconds:
\[ 2.95 \, \text{hours} = 2.95 \times 3600 \, \text{seconds} \]
Calculate the charge:
\[ Q = 2.18 \, \text{A} \times 2.95 \times 3600 \, \text{s} \]
\[ Q = 2.18 \times 10620 \, \text{C} \]
\[ Q = \text{Calculate the final result for precise charge.} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3fedbef1-4110-4bb3-9906-fd5663476380%2F871408da-4a57-43b1-a053-92a6a7f8210f%2F8u4k0t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Text:**
A current of 2.18 A is observed flowing through the cell for a period of 2.95 h. Calculate the amount of charge flowing through the circuit during this time.
---
**Explanation:**
This text is a problem statement commonly found in physics courses related to electricity. The task is to calculate the amount of electric charge (Q) that flows through a circuit when a known current (I) flows over a specified time period (t). In this case, a current of 2.18 amperes (A) flows for 2.95 hours (h).
**Calculation:**
To solve the problem, we use the formula:
\[ Q = I \times t \]
Where:
- \( Q \) is the charge in coulombs (C),
- \( I \) is the current in amperes (A),
- \( t \) is the time in seconds (s).
First, convert the time from hours to seconds:
\[ 2.95 \, \text{hours} = 2.95 \times 3600 \, \text{seconds} \]
Calculate the charge:
\[ Q = 2.18 \, \text{A} \times 2.95 \times 3600 \, \text{s} \]
\[ Q = 2.18 \times 10620 \, \text{C} \]
\[ Q = \text{Calculate the final result for precise charge.} \]
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