The amount of permanent set (deformation) used to determine the yield stress is usually... Select one: O a. 0.2 strain O b. none of these options O c. 210 GPa O d. 0.2% strain O e. 0.2% plastic deformation O f. 0.002%

The amount of permanent set (deformation) used to determine the yield stress is usually... Select one: O a. 0.2 strain O b. none of these options O c. 210 GPa O d. 0.2% strain O e. 0.2% plastic deformation O f. 0.002%

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A strain gauge is used to measure the shear strain on a shaft during torsional loading. The strain gauge is mounted such that it measures strain at an angle of 45° to the longitudinal axis of the shaft. The shear strain in the shaft is determined: a. as the strain measured by the strain gauge O b. by dividing the strain measured by the strain gauge by the shear modulus O c. None of these options O d. as twice the normal strain determined by the strain gauge.
12/. A rod of diameter 42 mm and 51.5 cm long having the modulus of elasticity is 286 MPa. During loading it excreted a strain of 0.3211. Calculate the stress in the rod in N/square millimeter. a. 89.7 b. 93.5 c. 79.8 d. 91.8
Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…
When the diameter of a specimen subjected to a twist test increases, the shear stress increases. Select one: O a. False O b. True
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1. A 0.015 meter diameter bar of steel is stress tested and the following stress-strain curve is produced Stress (psix 10 60 50 8 20 10 1 MPa 300 100 psi (x 10%) 50 200-30 OL 40- 20- 10 0.05 0.005 1 L 0.010 0.10 Strain a. What is the ultimate tensile strength (MPa)? d. What is the yield strength(MPa)? 0.15 c. What is the percent plastic elongation at the time of fracture? e. What is the Modulus of Elasticity (GPa)? 400 300 200 Stress (MPa) b. What is the greatest load that can be place on this bar before failure(N)? 100 10 0.20
What does normal strain measure? A. elongation per unit length B. Sum of elongation of different material C.original length per unit elongation D.None of the above
True stress-strain Engineering stress-strain strain Calculate the engineering ultimate tensile strength of a material whose strength coefficient is 535 MPa and of a tensile-test specimen that necks at a true strain of 0.55. 200 MPa O 267 MPa O 244 MPa O 222 MPa stress
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From the shear stress - shear strain diagram shown below, all the following are true except: Shear Stress (MPa) 500 450 400 350 300 250 200 150 100 50 0. 0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 Shear Strain (rad) Shear Stress-Strain Curve for Brass Select one: O a. Shear stress and Shear strain are 430 MPa and 1.72 rad at fracture. O b. Shear stress and Shear strain are 250 MPa and 0.05 rad at Yielding. Oc. The elastic zone ends at a shear stress of 400 MPa and shear strain of 1 rad Od. The ultimate Shear stress and Shear strain are 430 MPa and 1.72 rad.
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