The amount of Cd2+ in an aqueous sample was measured with a constant current coulometric technique. If a current of 53.6 mA required 178 s to reduce all of the Cd2+ to Cd what is the number of milligrams of Cd2+ in the solution?
The amount of Cd2+ in an aqueous sample was measured with a constant current coulometric technique. If a current of 53.6 mA required 178 s to reduce all of the Cd2+ to Cd what is the number of milligrams of Cd2+ in the solution?
From Faraday's First law of electrolysis, the amount of the substance deposited(W) at the given electrode is directly proportional to the quantity of charge(Q) passed through the electrolytic solution.
Mathematically it is given by W = ZQ
where Z = electrochemical equivalent = (E/F)
E = equivalent weight of Cd
F = Faraday's constant = 96500 C
But Q = it where i = current in amperes and t =time in seconds
i = current in amperes =
t = time in seconds = 178 s
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