The Alveolar Air Equation 11/4/2020 Practice Homework Due Wednesday Carli Amodio BS, RRT 1. What is the partial pressure exerted by each of the following gases if barometric pressure is 760mmHg? -Gas #147% -Gas #2 29% -Gas #3 68% Gas #147% 0.97x760=357.2mmity Gust 2 297 Gas #3 68% -0.68x760-516.8 mmHg 0.29×760=2204 mmHg 2. Mr. Smith's morning ABG on 40% O2 revealed a PaO2 of 72mmHg and PaCO2 of 56mmHg If PB=760 and PH20=47, calculate the alveolar air equation PAO2 = (PB-Palt20) X FI02- PaCO2-(760 mmHg-47mmHg) 2014- Paco 0.8 Paoa/PAO2 PAD (713) X04-08 2a. Determine Mr. Smith's a/A ratio Actual Pao2 72/195.2 = 0.3688 32 72mmHg 6.8 ₤4% PA02-285.2-72 0.8 PA02-285.2-90₤195.2mi 12mmHg| want 720x)=40 72. X=0.5 250% 20.4 2b. What FiO2 is needed to achieve a 102 of 100mmHg? have 72 mmalty 0.4 100 mmHg 72 x 3. Mrs. Smith's afternoon ABG on 32% 02 revealed a PaO2 of 60mmHg and PaCO2 of 59mmHg. If PB-720 and PH20=47, calculate Mrs. Smith's a/A ratio. 0.8 PAO2 = (PB- Patt20) XF102 - Pacoa PAO2 = (720mm 47 mmHg) 20.32- ratio a/A 59mmitg 0.8 Раск./Радя =673x0.32-64mmolly 215.36 - Almani 3a. Based on the results of #3, determine what FiO2 is needed to achieve a PaO2 of 0.8 90mmHg = 60mmity/141.61mmtig 0.423 42% 60mmHg 042 90mmHg X% 215.36-73.75 141.61 60(x)=37.8 = 0.63263%

The Alveolar Air Equation 11/4/2020 Practice Homework Due Wednesday Carli Amodio BS, RRT 1. What is the partial pressure exerted by each of the following gases if barometric pressure is 760mmHg? -Gas #147% -Gas #2 29% -Gas #3 68% Gas #147% 0.97x760=357.2mmity Gust 2 297 Gas #3 68% -0.68x760-516.8 mmHg 0.29×760=2204 mmHg 2. Mr. Smith's morning ABG on 40% O2 revealed a PaO2 of 72mmHg and PaCO2 of 56mmHg If PB=760 and PH20=47, calculate the alveolar air equation PAO2 = (PB-Palt20) X FI02- PaCO2-(760 mmHg-47mmHg) 2014- Paco 0.8 Paoa/PAO2 PAD (713) X04-08 2a. Determine Mr. Smith's a/A ratio Actual Pao2 72/195.2 = 0.3688 32 72mmHg 6.8 ₤4% PA02-285.2-72 0.8 PA02-285.2-90₤195.2mi 12mmHg| want 720x)=40 72. X=0.5 250% 20.4 2b. What FiO2 is needed to achieve a 102 of 100mmHg? have 72 mmalty 0.4 100 mmHg 72 x 3. Mrs. Smith's afternoon ABG on 32% 02 revealed a PaO2 of 60mmHg and PaCO2 of 59mmHg. If PB-720 and PH20=47, calculate Mrs. Smith's a/A ratio. 0.8 PAO2 = (PB- Patt20) XF102 - Pacoa PAO2 = (720mm 47 mmHg) 20.32- ratio a/A 59mmitg 0.8 Раск./Радя =673x0.32-64mmolly 215.36 - Almani 3a. Based on the results of #3, determine what FiO2 is needed to achieve a PaO2 of 0.8 90mmHg = 60mmity/141.61mmtig 0.423 42% 60mmHg 042 90mmHg X% 215.36-73.75 141.61 60(x)=37.8 = 0.63263%