The active ingredient in Antabuse, a drug used for the treatment of chronic alcoholism, is tetraethylthiuram disulfide, (C,H5),NCSSCN(C,H5)2 (296.54 g/mol). The sulfur in a 0.4329-g sample of an Antabuse preparation was oxidized to SO,, which was absorbed in H,O, to give H,SO4. The acid was titrated with 22.13 mL of 0.03736 M base. Calculate the percentage of ac- tive ingredient in the preparation.

The active ingredient in Antabuse, a drug used for the treatment of chronic alcoholism, is tetraethylthiuram disulfide, (C,H5),NCSSCN(C,H5)2 (296.54 g/mol). The sulfur in a 0.4329-g sample of an Antabuse preparation was oxidized to SO,, which was absorbed in H,O, to give H,SO4. The acid was titrated with 22.13 mL of 0.03736 M base. Calculate the percentage of ac- tive ingredient in the preparation.

Chemistry

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

9-16. The active ingredient in Antabuse, a drug used
for the treatment of chronic alcoholism, is
tetraethylthiuram disulfide,
S
(C,H3),NCSSCN(C,H3),
(296.54 g/mol). The sulfur in a 0.4329-g sample
of an Antabuse preparation was oxidized to
SO,, which was absorbed in H,O, to give
H,SO4. The acid was titrated with 22.13 mL of
0.03736 M base. Calculate the percentage of ac-
tive ingredient in the preparation.

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