A 5.276 g sample of Al-Mg alloy is digested in nitric acid (to Al*3 and Mg"). The solution is diluted to 500.00 mL and three 100.00 mL aliquots are treated with ammonia, the resulting Al(OH)3 precipitate is dried and then ignited to alumina, Al2O3 (MM = 101.961 g/mol). If the average mass of alumina obtained was 1.444 g, what was the percentage of aluminum (MM = 26.9815 g/mol) in the original sample?

A 5.276 g sample of Al-Mg alloy is digested in nitric acid (to Al*3 and Mg"). The solution is diluted to 500.00 mL and three 100.00 mL aliquots are treated with ammonia, the resulting Al(OH)3 precipitate is dried and then ignited to alumina, Al2O3 (MM = 101.961 g/mol). If the average mass of alumina obtained was 1.444 g, what was the percentage of aluminum (MM = 26.9815 g/mol) in the original sample?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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