The 92-kg man dives from the 41-kg canoe. The velocity indicated in the figure is that of the man relative to the canoe just after loss of contact. If the man, woman, and canoe are initially at rest, determine the horizontal component of the absolute velocity of the canoe (positive if to the right, negative if to the left) just after separation. Neglect drag on the canoe, and assume that the 52-kg woman remains motionless relative to the canoe. 2.4 m/s 34 92 kg 52 kg 41 kg Answer: Veanoe = 0.989 m/s

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Chapter1: Units, Trigonometry. And Vectors
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The 92-kg man dives from the 41-kg canoe. The velocity indicated in the figure is that of the man relative to the canoe just after loss of
contact. If the man, woman, and canoe are initially at rest, determine the horizontal component of the absolute velocity of the canoe
(positive if to the right, negative if to the left) just after separation. Neglect drag on the canoe, and assume that the 52-kg woman
remains motionless relative to the canoe.
2.4 m/s
34
92 kg
52 kg
41 kg
Answer: Vanos
m/s
0.989
Transcribed Image Text:Incorrect The 92-kg man dives from the 41-kg canoe. The velocity indicated in the figure is that of the man relative to the canoe just after loss of contact. If the man, woman, and canoe are initially at rest, determine the horizontal component of the absolute velocity of the canoe (positive if to the right, negative if to the left) just after separation. Neglect drag on the canoe, and assume that the 52-kg woman remains motionless relative to the canoe. 2.4 m/s 34 92 kg 52 kg 41 kg Answer: Vanos m/s 0.989
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