help **Physics Problem: Block and Wedge System**A small block of mass \( m_1 = 0.480 \) kg is released from rest at the top of a curved wedge. The wedge has a mass \( m_2 = 8.90 \) kg and sits on a frictionless horizontal surface, as shown in Figure (a). When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right, as shown in Figure (b).**Questions:**(a) **What is the velocity of the wedge after the block reaches the horizontal surface?** - Answer: \( 0.216 \, \text{m/s} \) (The magnitude of the velocity) ✓(b) **What is the height \( h \) of the wedge?** - Your attempt: \( 0.383 \, \text{m} \) ✗ - Note: Your response differs from the correct answer by more than 10%. Double-check your calculations.**Diagram Explanation:**- **Figure (a)**: Shows the block \( m_1 \) at the top of the wedge \( m_2 \).- **Figure (b)**: Shows the block \( m_1 \) moving at 4.00 m/s to the right after leaving the wedge.This problem illustrates the conservation of momentum and energy in a system of interacting bodies on a frictionless surface.

(a) using conservation of momentum m1v1+m2v2=m1u1+m2u2m1v1+m2v2=0v2=-m1v1m2=-0.480 kg4.00m/s8.90 kg=-0.2157 m/s≈-0.216 m/sUsing conservation of energy Kf+Uf=Ki+Ui12m1v12+12m2v22+0=0+m1ghg=m1v12+m2v222m1g=0.480 kg4.00m/s2+8.90 kg-0.2157 m/s220.480 kg9.8 m/s2=0.8603 m≈0.860 m

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A small block of mass m, = 0.480 kg is released from rest at the top of a curved wedge of mass m, = 8.90 kg, which sits on a frictionless horizontal surface as in figure (a). When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right, as in figure (b). h m2 m2 4.00 m/s (a) What is the velocity of the wedge after the block reaches the horizontal surface? (Enter the magnitude of the velocity.) 0.216 m/s (b) What is the height h of the wedge? 0.383

A small block of mass m, = 0.480 kg is released from rest at the top of a curved wedge of mass m, = 8.90 kg, which sits on a frictionless horizontal surface as in figure (a). When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right, as in figure (b). h m2 m2 4.00 m/s (a) What is the velocity of the wedge after the block reaches the horizontal surface? (Enter the magnitude of the velocity.) 0.216 m/s (b) What is the height h of the wedge? 0.383

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Physics Problem: Block and Wedge System**

A small block of mass \( m_1 = 0.480 \) kg is released from rest at the top of a curved wedge. The wedge has a mass \( m_2 = 8.90 \) kg and sits on a frictionless horizontal surface, as shown in Figure (a). When the block leaves the wedge, its velocity is measured to be 4.00 m/s to the right, as shown in Figure (b).

**Questions:**

(a) **What is the velocity of the wedge after the block reaches the horizontal surface?**
- Answer: \( 0.216 \, \text{m/s} \) (The magnitude of the velocity) ✓

(b) **What is the height \( h \) of the wedge?**
- Your attempt: \( 0.383 \, \text{m} \) ✗
- Note: Your response differs from the correct answer by more than 10%. Double-check your calculations.

**Diagram Explanation:**

- **Figure (a)**: Shows the block \( m_1 \) at the top of the wedge \( m_2 \).
- **Figure (b)**: Shows the block \( m_1 \) moving at 4.00 m/s to the right after leaving the wedge.

This problem illustrates the conservation of momentum and energy in a system of interacting bodies on a frictionless surface.

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