The 4.00 kg block is attached to a vertical rod by means of two strings. When the system rotates about the axis of the rod, the strings are extended as shown in the (Figure 1) and the tension in the upper string is 76.0 N. Part C Find the number of revolutions per minute at which the lower cord just goes sla igure < 1 of 1 Express your answer in revolutions per minute. Πν ΑΣφ ? 1.25 m Vmin = 37.23 rev/min 2.00 m 4.00 kg 1.25 m
The 4.00 kg block is attached to a vertical rod by means of two strings. When the system rotates about the axis of the rod, the strings are extended as shown in the (Figure 1) and the tension in the upper string is 76.0 N. Part C Find the number of revolutions per minute at which the lower cord just goes sla igure < 1 of 1 Express your answer in revolutions per minute. Πν ΑΣφ ? 1.25 m Vmin = 37.23 rev/min 2.00 m 4.00 kg 1.25 m
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![The 4.00 kg block is attached to a vertical rod by means
of two strings. When the system rotates about the axis of
the rod, the strings are extended as shown in the
(Figure 1) and the tension in the upper string is 76.0 N.
Part C
Find the number of revolutions per minute at which the lower cord just goes slack.
Figure
1 of 1
Express your answer in revolutions per minute.
ΑΣφ
?
Vmin = 37.23
rev/min
1.25 m
2.00 m
4.00 kg
1.25 m
圓](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5b811c9-2420-44cf-ae17-569b6ab554cc%2Ff3e4b5cd-dfa8-4c19-a583-2598d3f30e38%2Fzs6tbfb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The 4.00 kg block is attached to a vertical rod by means
of two strings. When the system rotates about the axis of
the rod, the strings are extended as shown in the
(Figure 1) and the tension in the upper string is 76.0 N.
Part C
Find the number of revolutions per minute at which the lower cord just goes slack.
Figure
1 of 1
Express your answer in revolutions per minute.
ΑΣφ
?
Vmin = 37.23
rev/min
1.25 m
2.00 m
4.00 kg
1.25 m
圓
Expert Solution
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Step 1
If the lower string goes slack, then tension on the lower string will be zero.
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