The 10.00 V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that its positive terminal is now next to point a. The rest of the circuit is as shown in the figure. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A complex network Figure 2.00 2 10.00 V -ww+ a 1.00 25.00 V. 4.00 Ω b 10.00 Ω 1 of 1 3.00 Ω Part A Find the current through 3.00 resistor. Express your answer with the appropriate units. 13.00 = Submit Part B Value X Incorrect; Try Again; One attempt remaining Submit A Previous Answers Request Answer Find the current through 4.00 2 resistor. Express your answer with the appropriate units. 14.00 = Value Part C A 2 Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining ? ?

Q: (((Q3/ B))) : Find the value of (I total )for the circuit shown. E=400Volts 2ΚΩ 2KO 200mA 400mA…

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Q: In the figure the ideal batteries have emfs E, = 4.89 V and E2 = 10.2 V, the resistances are each…

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Q: In the figure the ideal batteries have emfs 8₁=4.89 V and 8-10.2 V, the resistances are each 2.410,…

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Q: Q 2. The circuit in the diagram R1 contains R1 = 2 kN, R2 = 3kN, C1 = 2 µF, C2 = 3 µF and ɛ = on…

A: Given: The circuit diagram is as follows. R1=2 kΩ, R2=3 kΩ, C1=2 μF, C2=3 μF, ε=120 V Introduction:…

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A: Given data: Time t=7×10-2s Voltage V = 20 V Resistances: R1=2 kΩR2=500 ΩR3=3 kΩ Capacitance: C=100…

Q: In the figure the ideal batteries have emfs E, = 4.89 V and E2 = 10.2 V, the resistances are each…

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Q: In the circuit shown in the figure. R1 = 10 0. R2- 120, R3- 200, V1-1.0v, V2=7.0V, and the batteries…

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A: I1 = 2 A V1 = 10 volts R1 = 6 ohmR2 = 4 ohm V2 = 14 volts

Q: Of the circuit below, C1 = 9 nF, C2 = 7 nF, C3 = 9 nF,  and V = 7 V. What is the equivalent…

A: Given data:  C1 = 9 nF C2 = 7 nF and C3 = 9 nF Battery voltage (V) = 7 V Required: The equivalent…

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Q: In the figure the ideal batteries have emfs &₁ = 4.89 V and ₂ = 10.2 V, the resistances are each…

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