Spontaneous heat transfer from hot to cold is an irreversible process. Calculate the total change in entropy if 4000 J of heat transfer occurs from a hot reservoir at Th = 600 K(327º C) to a cold reservoir at Tc = 250 K(−23º C) , assuming there is no temperature change in either reservoir. ThTmReversibleprocessDirect fromT, to T.ReversibleprocessToTeIrreversibleTwo reversible processesASirev = ASrevASirev = ASrev(a)(b)Figure 15.34 (a) Heat transfer from a hot object to a cold one is an irreversible process that produces an overall increase in entropy. (b) Thesame final state and, thus, the same change in entropy is achieved for the objects if reversible heat transfer processes occur between the twoobjects whose temperatures are the same as the temperatures of the corresponding objects in the irreversible process.

Change in entropy in the hot reservoir

Answered: Th Tm Reversible process Direct from T,…

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

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Spontaneous heat transfer from hot to cold is an irreversible process. Calculate the total change in entropy if 4000 J of heat transfer occurs from a hot reservoir at T_h = 600 K(327º C) to a cold reservoir at T_c = 250 K(−23º C) , assuming there is no temperature change in either reservoir.

Th
Tm
Reversible
process
Direct from
T, to T.
Reversible
process
To
Te
Irreversible
Two reversible processes
ASirev = ASrev
ASirev = ASrev
(a)
(b)
Figure 15.34 (a) Heat transfer from a hot object to a cold one is an irreversible process that produces an overall increase in entropy. (b) The
same final state and, thus, the same change in entropy is achieved for the objects if reversible heat transfer processes occur between the two
objects whose temperatures are the same as the temperatures of the corresponding objects in the irreversible process.

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