Test the hypothesis that the true proportion of males is greater than 45% at the a=0.07 level. Include check of assumptions, hypotheses, conclusion and interpretation. Edit View Insert Format Tools Table 12pt ✓ Paragraph | B IU A 2✓ T² v Hypothesis: Ha: The true proportion of males is greater than 45% Ho: The true proportion of males is less than or equal to 45% Assumptions: X Conclusions and Interpretations: Our p-value is = 0.05894, which is :

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Hello, just need help with the assumptions and the conclusion/interpretations from the code in the picture.

Test the hypothesis that the true proportion of males is greater than 45% at the a-0.07 level. Include
check of assumptions, hypotheses, conclusion and interpretation.
Edit View Insert Format Tools Table
12pt ✓ Paragraph B IUA
|
A V 2 :
T² V |
Hypothesis:
Ha: The true proportion of males is greater than 45%
Ho: The true proportion of males is less than or equal to 45%
Assumptions:
X
Conclusions and Interpretations: Our p-value is = 0.05894, which is |
Transcribed Image Text:Test the hypothesis that the true proportion of males is greater than 45% at the a-0.07 level. Include check of assumptions, hypotheses, conclusion and interpretation. Edit View Insert Format Tools Table 12pt ✓ Paragraph B IUA | A V 2 : T² V | Hypothesis: Ha: The true proportion of males is greater than 45% Ho: The true proportion of males is less than or equal to 45% Assumptions: X Conclusions and Interpretations: Our p-value is = 0.05894, which is |
177
> prop.test(90,177, alternative = "greater", p = .45, conf.level = .93, correct
1-sample proportions test without continuity correction
data: 90 out of 177, null probability 0.45
X-squared = 2.4453, df = 1, p-value = 0.05894
alternative hypothesis: true p is greater than 0.45
93 percent confidence interval:
0.4532539 1.0000000
sample estimates:
р
0.5084746
FALSE)
Transcribed Image Text:177 > prop.test(90,177, alternative = "greater", p = .45, conf.level = .93, correct 1-sample proportions test without continuity correction data: 90 out of 177, null probability 0.45 X-squared = 2.4453, df = 1, p-value = 0.05894 alternative hypothesis: true p is greater than 0.45 93 percent confidence interval: 0.4532539 1.0000000 sample estimates: р 0.5084746 FALSE)
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