Test the hypothesis that male students who participate in college athletics are more massive than other male students, at 0.01 level of significance.
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The mean body mass of 50 male students who showed above average participation in college athletics was 68.2 kg with a standard deviation of 2.5 kg, while 50 male students who showed no interest in such participation had a mean mass of 67.5 kg with a standard deviation of 2.8 kg. Test the hypothesis that male students who participate in college athletics are more massive than other male students, at 0.01 level of significance.
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- A manufacturer fills soda bottles. Periodically the company tests to see if there is a difference between the mean amounts of soda put in bottles of regular cola and diet cola. A random sample of 19 bottles of regular cola has a mean of 502.4 mL of soda with a standard deviation of 3.9 mL. A random sample of 11 bottles of diet cola has a mean of 499.6 mL of soda with a standard deviation of 4.7 mL. Test the claim that there is a difference between the mean fill levels for the two types of soda using a 0.10 level of significance. Assume that both populations are approximately normal and that the population variances are not equal since different machines are used to fill bottles of regular cola and diet cola. Let bottles of regular cola be Population 1 and let bottles of diet cola be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.A random sample of 50 bags of blue corn tortilla chips had a mean weight of 9.06 ounces, with a standard deviation of 0.05 ounces. A random sample of 50 jalapeno tortilla chips had a mean weight of 9.01 ounces, with a standard deviation of 0.03 ounces. At the 0.05 level of significance, test the claim that the mean fill of blue corn tortilla chip bags is the same as the mean fill of jalapeno tortilla chips.In 2018, a study was conducted that stated that the average commute time to work for Kern County residents was 22.6 minutes. Suppose you were hired to determine if the average commute time is different than it was in 2018. You randomly sample 87 individuals who commute to work from Kern county and you find that their average commute time was 20.8 minutes and you find the standard deviation of commute times for those 87 individuals was 3.6 minutes. Carry out the appropriate hypothesis test at the a = 0.05 level of significance to determine if the average commute time differs from what it was in 2018.
- The mean height of 50 male students who showed above-average participation in college athletics was 68.2 inches (in) with a standard deviation of 2.5 in, while 50 male students who showed no interest in such participation had a mean height of 67.5 in with a standard deviation of 2.8 in. Test the hypothesis that male students who participate in college athletics are taller than other male students at 0.1 level.A leasing firm claims that the mean number of miles driven annually, u, in its leased cars is less than 13,100 miles. A random sample of 50 cars leased from this firm had a mean of 13,003 annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is 1120 miles. Is there support for the firm's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. Ho :0 S H : (b) Determine the type of test statistic to use. (Choose one) D=0 (c) Find the value of the test statistic. (Round to three or more decimal places.) O#0 OO (d) Find the p-value. (Round to three or more decimal places.) (e) Can we support the leasing firm's claim that the mean number of miles driven…A leasing firm claims that the mean number of miles driven annually, µ, in its leased cars is less than 12,300 miles. A random sample of 80 cars leased from this firm had a mean of 12,150 annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is 3160 miles. Is there support for the firm's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If necessary, consult a list of formulas.) |(a) State the null hypothesis H, and the alternative hypothesis H . H, :0 H, :0 |(b) Determine the type of test statistic to use. (Choose one) O=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) OThe heart rates of a random sample of 29 casting workers is taken to decide whether the mean post-work heart rate of casting workers exceeds the normal working heart rate of 72 beats per minute (bpm). The 29 workers had a mean heart rate of 78.3bpm. Assuming that the population standard deviation of post-work heart rates of casting workers is 11.2bpm, Is there sufficient evidence at 3% level of significance to conclude that the mean post-work heart rate for casting workers exceeds the normal resting heart rate of 72bpm?Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of womenA leasing firm claims that the mean number of miles driven annually, μ, in its leased cars is less than 12,680 miles. A random sample of 50 cars leased from this firm had a mean of 11,632 annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is 2700 miles. Is there support for the firm’s claim at the 0.01 level significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below.During 2008, college work-study students earned a mean of $1478. Assume that a sample consisting of 25 of the work-study students at a large university was found to have earned a mean of $1503 during that year, with a standard deviation of $210. The null and alternative hypotheses are formulate to suggest that the average earnings of this university’s work-study students were significantly higher than the national mean. At 5% level of significance, do reject or fail to reject H0? Fail to reject H0 because t-statistic is less than 1.711 Fail to reject H0 because t- statistic is greater than 1.711 Fail to reject H0 because t- statistic is greater than -1.711 Fail to reject H0 because t- statistic is less than -1.711A manufacturer fills soda bottles. Periodically the company tests to see if there is a difference between the mean amounts of soda put in bottles of regular cola and diet cola. A random sample of 19 bottles of regular cola has a mean of 502.4 mL of soda with a standard deviation of 3.9 mL. A random sample of 11 bottles of diet cola has a mean of 499.6 mL of soda with a standard deviation of 4.7 mL. Test the claim that there is a difference between the mean fill levels for the two types of soda using a 0.10 level of significance. Assume that both populations are approximately normal and that the population variances are not equal since different machines are used to fill bottles of regular cola and diet cola. Let bottles of regular cola be Population 1 and let bottles of diet cola be Population 2. Step 3 of 3: Draw a conclusion and interpret the decision.A random sample of 68 bags of white cheddar popcorn weighed, on average,5.12 ounces with a standard deviation of 0.26 ounce. Test the hypothesis that mu equals 5.3 ounces against the alternative hypothesis, mu less than 5.3 ounces, at the 0.10 level of significance.SEE MORE QUESTIONS